Answer:
440mt/p gallons
Explanation:
We are told that one gallon of paint covers an area of p square feet. Knowing this then, the question becomes how much paint is needed to cover a stripe that is t inches wide and m miles long.
Let us first use the dimensions of the stripe to find how much area that is in square feet. A stripe is rectangular so we will calculate the area as follows:
Area of stripe = width x length
= t inches x m miles (we need to convert both to feet)
= (t inches x 1 ft/12 inches) x (m miles x 5280 ft/1 mi)
=440mt square feet
ow we can find out how much paint will be needed by using ratios
p square feet : 1 gallon
440mt square feet : x
x = 440mt/p gallons
Its <span>c.chromatography is the process of separating solutions on the basis of their boiling points </span>
Answer:
2.2×10^8
Explanation:
Cu(OH)2(s)<---------> Cu^2+(aq) + 2OH^-(aq) Ksp=2.2 x 10 ^-20
2H3O^+(aq) + 2OH^-(aq) <-------> 4H2O(l). Kw= 1×10^14
Cu^2+(aq) + 4H2O(l) <--------> [Cu(H2O)4]^2+(aq)
Overall ionic reaction:
Cu(OH)2(s) +2H3O^+(aq) <---------> [Cu(H20)4]^2+(aq)
Equilibrium constant for the reaction: Ksp×Kw= 2.2 x 10 ^-20 × (1/(1×10^-14))^2
Keq= 2.2×10^8
Kw= ion dissociation constant of water
M CH₃COOH: 12u×2 + 1u×4 + 16u×2 =<u> 60u</u>
m 9CH₃COOH: 60u×9 = <u>540u</u>
<em>(1u ≈ 1,66·10⁻²⁴g)</em>
-----------------------------
1u ------- <span>1,66·10⁻²⁴g
540u ---- X
X = 540</span>×<span>1,66·10⁻²⁴g
<u>X = 896,4</u></span><span><u>·10⁻²⁴g
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