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lawyer [7]
2 years ago
7

Only _____ live part of their lives like fish and the rest of their lives as land animals.

Chemistry
2 answers:
dedylja [7]2 years ago
6 0

Answer:

amphibians

Explanation:

because frogs have to stay in water while tadpole then they come to land

navik [9.2K]2 years ago
3 0

Answer:

Amphibians

Explanation:

It is amphibians.

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What happens to a sheet of copper as the average kinetic energy of the copper molecules decreases?
JulsSmile [24]

Answer:

<h2>It gets cooler.</h2>

Explanation:

<h2>Hopes this helps. Mark as brainlest plz!</h2>
8 0
3 years ago
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A que llamamos niveles y subniveles de energia?
Softa [21]

Answer:

agua

Explanation:

por que estamos en la planeta

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The combination of oxygen with other substances to produce new chemical products is called
Flauer [41]

Answer:

                 The combination of oxygen with other substances to produce new chemical products is called <u>Oxidation</u>.

Explanation:

                     Oxidation reactions are defined as,

In terms of Inorganic chemistry:

                 (i) <u>Removal of Electrons: </u>

                            Example:  Mg  →  Mg²⁺  +  2 e⁻

                (ii) <u>Addition of Oxygen:</u>

                            Example:  2 Mg  + O₂  →  2 MgO

In terms of Organic chemistry:

                (i) <u>Addition of Electrons: </u>

                            Example:  Cl₂  +  2 e⁻   →   2 Cl⁻

                (ii) <u>Addition of Hydrogen:</u>

                            Example:  H₂CCH₂  +  H₂    →   H₃CCH₃

4 0
3 years ago
What is avogrados number and why is it useful
gtnhenbr [62]

Answer:

Avogadro's number is 6.022×1023 molecules. With Avogadro's number, scientists can discuss and compare very large numbers, which is useful because substances in everyday quantities contain very large numbers of atoms and molecules.

please mark Brainliest if it helps!

7 0
2 years ago
Need help with 14 and 16 pls asap!! this is my friends test and im taking it tomorrow!!
marin [14]

Answer:

Q14: 17,140 g = 17.14 kg.

Q16: 504 J.

Explanation:

<u><em>Q14:</em></u>

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by ice (Q = 3600 x 10³ J).

m is the mass of the ice (m = ??? g).

c is the specific heat of the ice (c of ice = 2.1 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 100.0°C - 0.0°C = 100.0°C).

∵ Q = m.c.ΔT

∴ (3600 x 10³ J) = m.(2.1 J/g.°C).(100.0°C)

∴ m = (3600 x 10³ J)/(2.1 J/g.°C).(100.0°C) = 17,140 g = 17.14 kg.

<u><em>Q16:</em></u>

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by ice (Q = ??? J).

m is the mass of the ice (m = 12.0 g).

c is the specific heat of the ice (c of ice = 2.1 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 0.0°C - (-20.0°C) = 20.0°C).

∴ Q = m.c.ΔT = (12.0 g)(2.1 J/g.°C)(20.0°C) = 504 J.

6 0
3 years ago
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