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erica [24]
2 years ago
12

A sledgehammer hits a wall. How do the hammer and the wall act on each other? (1 point)

Physics
1 answer:
stellarik [79]2 years ago
5 0

Answer:

The hammer and the wall exert forces on each other that are equal in magnitude but in opposite directions.

Explanation:

currently doing corrections on the test!

:)

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The speed of an arrow fired from a compound
san4es73 [151]

Answer:

A.) The arrow`s range is 624,996 m

B.) The arrow`s range is 846.887 m, when the horse is galloping

Explanation:

We have a case of oblique movement. In these cases the movement in the X axis is a Uniform Rectelinear Movement (URM), and a Uniform Accelerated Movement (UAM) in the Y axis.

By the way, the equations that we use for the X axis will be from URM, and those for the Y axis wiil be from UAM.

<u>Equations</u>

X axis:

X=v_{ox}*t

v_{0x} =v_0cos(\alpha)

Y axis:

Y= Y_0 +v_{y0} t - \frac{g}{2} t^2

A.) First, it is necessary to know t, total time.

To figure out t value, we use UAM, since time is determined by this movement.

Now, at the end of the movement, Y=0, then

0= Y_0 +v_{y0} t - \frac{g}{2} t^2

0=2.4m+79m/s*sin(39)t-(1/2*9.81m/s^2)t^2

Caculate the segcond degree equation to obtain the two possible values for t:

t_1= 10.18 \\t_2= -0.04046

But, in physics, time it could not be negative, so we take t_1= 10.18

Caculate now:

X=79m/s*cos(\39)*10.18s= 624.996 m

B.) Now, the narrow has an additional speed, that could be sum to the speed due to the bow.

v_0= 79m/s+13m/s= 92m/s

Using the same procedure that item A, caculate X

First, we need to know the new time

0=2.4m+92m/s*sin(39)t-(1/2*9.81m/s^2)t^2

And we obtain:

t_1=11.845s\\t_2=-0.041s

One more time, we take the positive time: t_1=11.845s

Finally:

X=92m/s *cos(39)*11.845s=846.887 m

6 0
3 years ago
BRAINLIEST PLZ HELP!
balu736 [363]
The correct answer should be A
5 0
2 years ago
If you drop a bowling ball, a tennis ball, and a feather from the top of a tall building at the same time, which one will hit th
olasank [31]

They hit at the same time. Everything falls at the same rate.

8 0
3 years ago
Read 2 more answers
The first-order decomposition of cyclopropane has a rate constant of 6.7 × 10–4 s–1. If the initial concentration of cyclopropan
Ket [755]

Answer:

.864 M

Explanation:

For first order decomposition,

rate constant k = 1/t x ln a / (a - x )

given , a = 1.33 M , t = 644 s , k = 6.7 x 10⁻⁴ , a - x  = ? = b( let )

6.7 x 10 ⁻⁴ = 1/644 x ln 1.33/b

ln 1.33/b = 6.7 x 10⁻⁴ x 644 = .4315

1.33 / b = e⁰ ⁴³¹⁵ = 1.5395

b = 1.33 / 1.5395 = .864 M.

7 0
3 years ago
What is the result of (6.2 × 10 4) x (3.3 × 10 2) expressed in scientific notation?
Serjik [45]
In scientific notation there are some rules;
1) the decimal point is comes to the first non-zero degit.
2) if the decimal point comes from left to right the power of ten must be         negative.
3) if the decimal point comes from right to left then the power of 10 is possitive.
            the numberyou wrote is an scientific form.you must say that expressed in standard form.write brother.
8 0
3 years ago
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