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jasenka [17]
3 years ago
11

To reduce the drag coefficient and thus improve the fuel efficiency of cars,the design of side rearview mirrors has changed dram

atically in recent decades from asimple circular plate to a streamlined shape. Determine the amount of fuel and moneysaved per year as a result of replacing a 15-cm-diameter flat mirror by one with ahemispherical back. Assume the car is driven 25,000 km a year at an average speedof 95 km/hr. Take the density and price of gasoline to be 0.75 kg/L and $0.90/L,respectively; the heating value of gasoline to be 44,000 kJ/kg and the overall efficiencyof the engine to be 30 percent.
Engineering
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

Amount of fuel used per year is supposed to be 34150 KJ/kg

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In the first-order process,a blue dye reacts to form a purple dye. The amount of blue dye at the end of 1 hr is 480 g and the en
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Answer:

The answer is 960 kg

Explanation:

Solution

Given that:

Assume the initial dye concentration as A₀

We write the expression for the dye concentration for one hour as follows:

ln (C₁) = ln (A₀) -kt

Here

C₁ = is the concentration at 1 hour

t =time

Now

Substitute 480 g for C₁ and 1 hour for t

ln (480) = ln (A₀) -k(1) ------- (1)

6.173786 =  ln (A₀) -k

Now

We write the expression for the dye concentration for three hours as follows:

ln (C₃) = ln (A₀) -k

Here

C₃ = is the concentration at 3 hour

t =time

Thus

Substitute 480 g for C₃ and 3 hour for t

ln (120) = ln (A₀) -k(3) ------- (2)

4.787492 = ln (A₀) -3k

Solve for the equation 1 and 2

k =0.693

Now

Calculate the amount of blue present initially using the expression:

Substitute 0.693 for k in equation (2)

4.787492 = ln (A₀) -3 (0.693)

ln (A₀) =6.866492

A₀ =e^6.866492

= 960 kg

Therefore, the amount of the blue dye present from the beginning is  960 kg

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A safety interlock module operates by monitoring the voltage from the
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The compressor in a refrigerator compresses saturated R-134a vapor at 0°F to 200 psia. Calculate the work required by this compr
kvasek [131]

Answer:

The work required is W =  20.2 BTU per lbm

Explanation:

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Therefore work done

W = h_{1} - h_{2}

W = 103.1 - 123.3

W = - 20.2 BTU per lbm

Therefore the work required is W =  20.2 BTU per lbm

6 0
3 years ago
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