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jasenka [17]
3 years ago
11

To reduce the drag coefficient and thus improve the fuel efficiency of cars,the design of side rearview mirrors has changed dram

atically in recent decades from asimple circular plate to a streamlined shape. Determine the amount of fuel and moneysaved per year as a result of replacing a 15-cm-diameter flat mirror by one with ahemispherical back. Assume the car is driven 25,000 km a year at an average speedof 95 km/hr. Take the density and price of gasoline to be 0.75 kg/L and $0.90/L,respectively; the heating value of gasoline to be 44,000 kJ/kg and the overall efficiencyof the engine to be 30 percent.
Engineering
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

Amount of fuel used per year is supposed to be 34150 KJ/kg

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The type of current that flows from the electrode across the arc to the work is called what?
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Answer:

Direct current.

Explanation:

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3 years ago
An alloy is evaluated for potential creep deformation in a short-term laboratory experiment. The creep rate is found to be 1% pe
LenaWriter [7]

Answer:

a) Q = 251.758 kJ/mol

b) creep rate is    = 1.751 \times 10^{-5} \% per hr

Explanation:

we know Arrhenius expression is given as

\dot \epsilon =Ce^{\frac{-Q}{RT}

where

Q is activation energy

C is pre- exponential constant

At 700 degree C creep rate is\dot \epsilon = 5.5\times 10^{-2}% per hr

At 800 degree C  creep rate is\dot \epsilon = 1% per hr

activation energy for creep is \frac{\epsilon_{800}}{\epsilon_{700}} = = \frac{C\times e^{\frac{-Q}{R(800+273)}}}{C\times e^{\frac{-Q}{R(700+273)}}}

\frac{1\%}{5.5 \times 10^{-2}\%} = e^{[\frac{-Q}{R(800+273)}] -[\frac{-Q}{R(800+273)}]}

\frac{0.01}{5.5\times 10^{-4}} = ln [e^{\frac{Q}{8.314}[\frac{1}{1073} - \frac{1}{973}]}]

solving for Q we get

Q = 251.758 kJ/mol

b) creep rate at 500 degree C

we know

C = \epsilon e^{\frac{Q}{RT}}

    =- 1\% e{\frac{251758}{8.314(500+273}} = 1.804 \times 10^{12} \% per hr

\epsilon_{500} = C e^{\frac{Q}{RT}}

                         = 1.804 \times 10^{12}  e{\frac{251758}{8.314(500+273}}

                         = 1.751 \times 10^{-5} \% per hr

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2 years ago
A(n)___ branch circuit supplies two or more receptacles or outlets for lighting and appliances
Juli2301 [7.4K]

Answer: General purpose branch circuit

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General purpose branch circuit are the type of circuits that are used mainly to supply light to two or more receptacle outlets for small appliances. This circuits are about 120v can be used either in residential, commercial and industrial buildings.

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What's the monomer? Show the structure.
ivolga24 [154]

In order to understand a monomer let´s first see the structure of a polymer. As an example, in the first figure polyethylene (or polyethene) is shown. This polymer, like every other one, is composed of many repeated subunits, these subunits are called monomer. In the second figure, polyethylene's monomer is shown.  

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