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iragen [17]
3 years ago
11

The synodic period for a planet is different from its sidereal period because

Physics
1 answer:
IrinaK [193]3 years ago
5 0
<span>Earth (and hence the observer) moves.</span>
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6. Can an object accelerate, but not speed up or slow down?<br> Explain:
FromTheMoon [43]

Answer:

yes, though the speed may stay constant, the direction will change. so for example, you're going 70mph on the freeway, but you have to take the exit on your right (the exit continues on to a different freeway), you're not going to speed up or slow down, you'll change your direction which is still accelerating.

Explanation:

Credit goes to @naeAF

Hope this helps :))

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3 years ago
Diego hypothesizes that the Earth wobbles on its axis in a pattern that is repeated every 20,000 years.
DedPeter [7]

Answer:

D. make a model

Explanation:

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3 years ago
A 15 m ladder with a mass of 51 kg is leaning against a frictionless wall, which makes an angle of 60 degrees with the horizonta
timofeeve [1]

Answer:

Explanation:

Given that, .

Mass of ladder is 51kg

Then, it weight is

WL = mg = 51 × 9.81 = 500.31N

This weight will act at the midpoint of the ladder

Length of ladder is 15m

The ladder makes an angle 55°C with the horizontal

An object whose mass is 81kg is at 4m from the bottom of the ladder

Then, weight of object

Wo = mg = 81 × 9.81 = 794.61 N

Using newton second law

Check attachment

Ng is normal force on the ground

Ff is the horizontal frictional force

Nw Is the normal force on the wall

ΣFy = 0

Ng = Wo + WL

Ng = 794.61 + 500.31

Ng = 1294.92 N

Also

ΣFx = 0

Ff — Nw = 0

Then,

Ff = Nw

Now taking moment about point A.

Check attachment

using the principle of equilibrium

Sum of clockwise moment equals to sum of anti-clockwise moment

Also note that the Normal force on the wall is not perpendicular to the ladder, so we will resolve that and also the weights of ladder and weight of object

Clockwise = Anticlockwise

Wo•Cos60 × 4 + WL•Cos60 × 7.5 = Nw•Sin60 × 15

794.61Cos60 × 4 + 500.31Cos60 × 7.5 = Nw × Sin60 × 15

1589.22 + 1876.163 = 12.99•Nw

3465.383 = 12.99•Nw

Nw = 3465.383 / 12.99

Nw = 266.77 N

Since, Nw = Ff

Then, Ff = 266.77N

the horizontal force exerted by the ground on the ladder is 266.77 N

8 0
3 years ago
Read 2 more answers
What are the applications of pascal's principle​
Murrr4er [49]

Explanation:

  • The applications are, hydraulic lift- to transmit equal pressure throughout a fluid.
  • Hydraulic jack- used in the braking system of cars.
  • use of a straw- to suck fluids, which goes because of air pressure.
<h3>The question simply asks, where pressure can be applied. There are many others, such as <em><u>l</u></em><em><u>i</u></em><em><u>f</u></em><em><u>t</u></em><em><u> </u></em><em><u>p</u></em><em><u>u</u></em><em><u>m</u></em><em><u>p</u></em><em><u>.</u></em></h3>
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All of the following statements are true of hydroelectric power EXCEPT: A. Hydroelectric power stations rely on dams to help har
Artist 52 [7]
The correct answer should be C. Hydroelectric power stations can only produce enough energy for a small town as they do not produce large quantities

Hydroelectric power stations can power even large cities that have millions of people.
5 0
3 years ago
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