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SCORPION-xisa [38]
2 years ago
13

Please please help me, don't guess please my test is timed !!

Physics
1 answer:
dimulka [17.4K]2 years ago
4 0

Answer:

a) J = F  t = 40 * .05 = 2 N-s

b)  J = 2 N-s     momentum changed by 2 N-s

c) Initial momentum appears to be zero

J = change in momentum = m v2 - m v1 = m v2 = 2 N-s

v2 = J / m = 2 / .057 = 35 m/s

d) if the impulse time was increased and the average force remained the same then the change in momentum would increase with a corresponding increase in velocity attained - note the increase in v2 in part c)

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An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.300 rev/s . The magnitude
Salsk061 [2.6K]

1) 1.2 m/s

First of all, we need to find the angular velocity of the blade at time t = 0.200 s. This is given by

\omega_f = \omega_i + \alpha t

where

\omega_i = 0.300 rev/s is the initial angular velocity

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Substituting t = 0.200 s, we find

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2) 2.25 m/s^2

The tangential acceleration of a point rotating at a distance r from the centre of the circle is

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First of all, we need to convert the angular acceleration into rad/s^2:

\alpha = 0.895 rev/s^ \cdot 2 \pi =5.62 rad/s^2

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3) 3.6 m/s^2

The centripetal acceleration is given by

a=\frac{v^2}{r}

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r is the distance from the centre of the circle

We already calculate the tangential speed at point a):

v = 1.2 m/s

while the distance of a point at the end of the blade from the centre is

r = 0.400 m

Therefore, the centripetal acceleration is

a=\frac{1.2^2}{0.400}=3.6 m/s^2

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