Answer:
x = 0.0756 m
Fred moves in the direction where Brutus moves
Explanation:
This exercise is for the moment, we define the system as formed by the two players, for this system the forces in the clash are internal, so the moment is preserved
Initial. Before the crash
p₀ = m v₀₁ - M v₀₂
Final. After the crash
= (m + M) v
p₀ = 
m v₀₁ –M v₀₂ = (m + M) v
v = (m v₀₁ - M v₀₂) / (m + M)
Let's calculate
v = (60 6 - 120 4) / (60 +120)
v = - 120/180
v = - 0.667 m / s
The negative sign indicates that the final speed is the direction where Brutus runs
Let's use Newton's second law to find the acceleration of the two players
fr = (m + M) a
fr = μ N
N- W = 0
N = (m + M) g
μ (m + M) g = (m + M) a
a = μ g
a = 0.30 9.8
a = 2.94 m / s²
We use kinematics to find the distance traveled, the final speed is zero
v² = v₀² - 2 a x
x = v₀² / 2 a
x = 0.667² / (2 2.94)
x = 0.0756 m
The vertical movement of the projectile is described by:
y = H - gt² / 2
When the cannonball is on the ground, y= 0 so:
0 = H - gt² /2
Solving for t:

The horizontally movement of the projectile is described by:
x = v₀t
Solving for v₀:
v₀ = x/t
v₀ = 175 m / 2.8 s
v₀ = 61.5 m/s
<span>Newton's third law is that for every action, there is an equal and opposite reaction.
A </span><span>Damage is not a part of physics, at least I don't think it is. </span><span>
B </span>Is just downright wrong. If anything, the smaller mass will be pushed forward with the heavier mass. <span>
C Sounds correct
D It'</span><span>s wrong, because the masses are not equal, or else they would stop.</span>
Vector is perpendicular to x axis or i component.
Hence i component is 0
j component is 63.5

Answer:
it depends on the relative masses of the objects.
Explanation: