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3 years ago

You are standing on the ground. Describe two ways that you could increase the pressure between your feet and the ground.

Physics

1 answer:

ch4aika [34]3 years ago

3 0

Answer:

1:by standing with one feet

2:by standing with your toes

Explanation:

1: by standing with one feet

2:by standing with ur toes

Pressure is inversely proportional to area, the little the area, the more the pressure.the bigger the area,the lesser the pressure

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The moment of inertia for a 5500 kg solid disc is 12100 kg-m^2. Find the radius of the disc? (a) 2.111 m (b) 2.579 m (c) 1.679

Soloha48 [4]

Answer:

The radius of the disc is 2.098 m.

(e) is correct option.

Explanation:

Given that,

Moment of inertia I = 12100 kg-m²

Mass of disc m = 5500 kg

Moment of inertia :

The moment of inertia is equal to the product of the mass and square of the radius.

The moment of inertia of the disc is given by

$I=\dfrac{mr^2}{2}$

Where, m = mass of disc

r = radius of the disc

Put the value into the formula

$12100=\dfrac{5500\times r^2}{2}$

$r=\sqrt{\dfrac{12100\times2}{5500}}$

$r= 2.098\ m$

Hence, The radius of the disc is 2.098 m.

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2 years ago

The town hall building is situated close to Boojho’s house. There is a clock on the top of the town hall building which rings th

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At night we experience quietness more. At this time, sounds of object will be heard more clearer

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3 years ago

Why does Usain bolt run?

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Answer:

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Explanation:

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1 year ago

Fill in the blanks for the following:

storchak [24]

Answer:

a. 4.21 moles

b. 478.6 m/s

c. 1.5 times the root mean square velocity of the nitrogen gas outside the tank

Explanation:

Volume of container = 100.0 L

Temperature = 293 K

pressure = 1 atm = 1.01325 bar

number of moles n = ?

using the gas equation PV = nRT

n = PV/RT

R = 0.08206 L-atm- $mol^{-1}$ $K^{-1}$

Therefore,

n = (1.01325 x 100)/(0.08206 x 293)

n = 101.325/24.04 = 4.21 moles

The equation for root mean square velocity is

Vrms = $\sqrt{\frac{3RT}{M} }$

R = 8.314 J/mol-K

where M is the molar mass of oxygen gas = 31.9 g/mol = 0.0319 kg/mol

Vrms = $\sqrt{\frac{3*8.314*293}{0.0319} }$ = 478.6 m/s

For Nitrogen in thermal equilibrium with the oxygen, the root mean square velocity of the nitrogen will be proportional to the root mean square velocity of the oxygen by the relationship

$\frac{Voxy}{Vnit}$ = $\sqrt{\frac{Mnit}{Moxy} }$

where

Voxy = root mean square velocity of oxygen = 478.6 m/s

Vnit = root mean square velocity of nitrogen = ?

Moxy = Molar mass of oxygen = 31.9 g/mol

Mnit = Molar mass of nitrogen = 14.00 g/mol

$\frac{478.6}{Vnit}$ = $\sqrt{\frac{14.0}{31.9} }$

$\frac{478.6}{Vnit}$ = 0.66

Vnit = 0.66 x 478.6 = 315.876 m/s

the root mean square velocity of the oxygen gas is

478.6/315.876 = 1.5 times the root mean square velocity of the nitrogen gas outside the tank

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