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Tcecarenko [31]
3 years ago
11

You endanger a swimmer with the wake from your boat. under minnesota boating laws, what have you done?

Physics
1 answer:
mixas84 [53]3 years ago
8 0

The following enumeration is the list of actions which are considered to be illegal when operating your boat:

1   Operating the boat in a harsh or inconsiderate manner

2   Operating the boat in the absence of safety equipment

3   Actual weight exceeds the carrying capacity of the boat

4   Not prohibiting the riders to sit on gunwales, transom, stern, sides, bow or decking over the bow sides when the boat is underway, except when sufficient guards or railings are provided

5   Operating the boat or giving permission to other people to operate the boat while drunk or under illegal substances

6   Operating the boat and the wash or wake endanger any property or person

7   Operating the boat in an area designated for swimming

8   Operating the boat beyond a slow, no wake speed in locations marked as no wake zones

 

We can see that in this case, the rule # 6 is being trespassed. Therefore under Minnesota Boating Laws, we have committed an Illegal Operating Practice.

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A=100m/s2<br> Vi=10m/s<br> T=10sec<br> Vf?
IrinaK [193]

Answer:

v=u+at

v= 10+100×10

v = 10+1000

v = 1010 m/s

3 0
3 years ago
Convert 13.6g/cm3 into kg/m3​
Wewaii [24]

Answer:

0.000136kg/m3

Explanation:

13.6 / 1000 = 0.0136kg/cm3

0.0136 / 100 = 0.000136kg/m3

5 0
3 years ago
A 2kg watermelon is dropped from a 4m tall roof a) use the appropriate kinematic equations to determine the instantaneous veloci
Ivenika [448]

Answer:

8.85m/s

Explanation:

The potential energy the watermelon held before dropping is Ep=mgh=2*9.8*4=78.4J.

When it strikes the ground, all of its Ep will transfer into Ek, so 1/2*m*v^2=78.4.

We already knew that m=2, so insert that in, we will get the V^2=78.4 m/s, V=8.85 m/s

6 0
3 years ago
An automobile is traveling away from Jill and towards Jack. The horn is honking, producing a sound wave.
wlad13 [49]

Answer:

a. The sound will travel at the speed to both Jill and Jack

b. Jack

Explanation:

a. Doppler effect describes how the frequency of a sound wave changes with regards to an observer that has relative motion to the sound source;

The Doppler effect is given by the following formula;

For a sound that is moving away, as observed by Jill, we have;

f' = \dfrac{(v - v_0)}{(v + v_s)} \cdot f =  \dfrac{v }{(v + v_s)} \cdot f

For approaching sound, as observed by Jack, we have;

f' = \dfrac{(v + v_0)}{(v - v_s)} \cdot f =  \dfrac{v }{(v - v_s)} \cdot f

Where;

f = The sound wave's actual frequency

f' = The frequency of the moving sound to the observer

v = The speed of the sound wave

v₀ = The observer's velocity = 0

v_s = The velocity of the source (the automobile honking) of the sound wave

From the above equation, we have that the speed of sound, 'v', is the same to both the source, and the observer although the frequency, and therefore, the wavelength of the sound alternatively increases or decreases

b. From the Doppler effect equation, the person who will hear the highest frequency is given by the formula for the frequency when the sound is approaching the observer, which has the lower denominator

Therefore, given that the automobile is travelling towards Jack, jack will hear the higher frequency

5 0
3 years ago
PROBLEMA DI FISICA:il volume di un attizzatoio da camino in ferro, a temperatura ambiente (20°C), è 12,2 cm cubi. A contatto con
lesantik [10]

Responder:

20.3 ° C

Explicación:

<u>Según la ley de Charles</u>: <em>cuando la presión sobre una muestra de gas seco se mantiene constante, la temperatura y el volumen estarán en proporción directa. </em>

Paso uno:

datos dados

Temperatura T1 = 20 ° C

Temperatura T2 =?

Volumen V1 = 12.2 cm ^ 3

Volumen V2 = 12.4 cm ^ 3

Aplicar la relación temperatura y volumen

\frac {V_{1}}{T_{1}}=\frac {V_{2}}{T_{2}}

sustituyendo tenemos

\frac {12.2}{20}=\frac {12.4}{T_{2}}\\\\

Cruz multiplicar tenemos

T_2=\frac{20*12.4}{12.2} \\\\T_2=\frac{248}{12.2}\\\\T_2=20.3

Temperatura delle braci 20.3°C

4 0
3 years ago
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