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2 years ago

Noah drops a rock with a density of 1.73 g/cm3 into a pond. Will the rock float or sink? Explain your answer.

Physics

2 answers:

umka21 [38]2 years ago

7 0

The rock will sink because the rock is denser than the water

aalyn [17]2 years ago

3 0

Answer: It sinks

Explanation: Density of water is approximately $1.0 gcm^{-3}$

Any substance that has higher density than that of water will sink and any substance that has density lesser than water will float.

$Density=\frac{mass}{volume}$

Thus a higher density substance has more mass for the amount of volume it displaces and hence it sinks.

When Noah drops a rock in water, the rock will sink as it has a higher value of density $(1.73gcm^{-3})$ than that of water $(1.0 gcm^{-3})$

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Tems11 [23]

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3 years ago

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Ulleksa [173]

Answer:

¹/₃₈₇ second

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3 years ago

A sound source is moving at 80 m/s toward a stationary listener that is standing in still air (a) Find the wavelength of the sou

Setler [38]

Answer:

a. wavelength of the sound, $\vartheta = 1.315\vartheta_{o}$

b. observed frequecy, $\lambda = 0.7604\lambda_{o}$

Given:

speed of sound source, $v_{s}$ = 80 m/s

speed of sound in air or vacuum, $v_{a}$ = 343 m/s

speed of sound observed, $v_{o}$ = 0 m/s

Solution:

From the relation:

v = $\vartheta \lambda$ (1)

where

v = velocity of sound

$\vartheta$ = observed frequency of sound

$\lambda$ = wavelength

(a) The wavelength of the sound between source and the listener is given by:

$\lambda = \frac{v_{a}}{\vartheta }$ (2)

(b) The observed frequency is given by:

$\vartheta = \frac{v_{a}}{v_{a} - v_{s}}\vartheta_{o}$

$\vartheta = \frac{334}{334 - 80}\vartheta_{o}$

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Using eqn (2) and (3):

$\lambda = \frac{334}{1.315} = \frac{1}{1.315}\frac{v_{a}}{\vartheta_{o}}$

$\lambda = 0.7604\lambda_{o}$

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3 years ago

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