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NNADVOKAT [17]
2 years ago
10

What is displacemnet

Physics
2 answers:
allsm [11]2 years ago
7 0

Answer:

to move an object from its place or position

Explanation:

if you move an object from where it first was

ser-zykov [4K]2 years ago
4 0
To move a object where u don’t remember where u put it or not putting someone thing in the right place or area
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A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long
Degger [83]

Answer:

(A). The work done by friction in crossing the patch is -637.98 J.

(B). The speed of skier is 10.57 m/s.

Explanation:

Given that,

Mass of skier = 62 kg

Speed = 6.5 m/s

Length = 3.50 m

Coefficient kinetic friction = 0.30

Height = 2.5 m

(A) we need to calculate the work done by friction in crossing the patch

Using formula of work done

W=-\mu mg\times l

Put the value into the formula

W=-0.30\times62\times9.8\times3.50

W=-637.98\ J

The work done by friction in crossing the patch is -637.98 J.

(B) we need to calculate the speed of skier

Using conservation of energy

K.E_{i}+U_{i}-W_{friction}=K.E_{f}+U_{f}

\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2+U_{f}

Final potential energy is zero

So, \dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}v_{1}^2+gh-\mu gl

Put the value into the formula

\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}\times6.5^2+9.8\times2.5+0.30\times9.8\times3.50

v_{2}=\sqrt{2\times55.915}

v_{2}=10.57\ m/s

The speed of skier is 10.57 m/s.

Hence,  (A).The work done by friction in crossing the patch is -637.98 J.

(B).The speed of skier is 10.57 m/s.

6 0
3 years ago
an object has a momentum of 250 kg m/s what would be the momentum of an object that has half of the mass and going at the same v
Romashka-Z-Leto [24]

The momentum of the second object is 125 kg m/s

Explanation:

The momentum of an object is given by

p=mv

where

m is the mass of the object

v is its velocity

For the object in this problem,

p = 250 kg m/s

And its mass is m and its velocity is v.

The second object has a mass of m' = \frac{m}{2} and same velocity v, so its momentum is

p'=m'v = (\frac{m}{2})v=\frac{1}{2}(mv)=\frac{1}{2}p

So, the second object has a momentum that is half of the momentum of the first object, therefore it is:

p'=\frac{1}{2}(250)=125 kg m/s

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

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3 years ago
The micturition reflex can be voluntarily controlled by the
ki77a [65]

Answer:

The micturition reflex can be voluntarily controlled by the relaxation of the external urethral sphincter.

3 0
2 years ago
When scientists describe the position of an object accurately, they use a _______________ point.
Radda [10]
I’m pretty sure it’s a starting point... unless it’s asking for an actual object
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Have suxhebeuxhsbendixbebendue bride. Did e did e end Rudd. R
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