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zhannawk [14.2K]
2 years ago
10

An object with a mass of 70.5 kg is placed on a 2-meter strand of metal (with a 2-millimeter radius) hanging from the ceiling. I

t stretches 1 millimeter. What is this strand made of?
Physics
1 answer:
Gennadij [26K]2 years ago
3 0

Based on the value of the Young's modulus, the strand of the metal is made of copper.

<h3>Young's modulus of the metal</h3>

The Young's modulus of the metal is calculated as follows;

E = stress/strain

<h3>Stress of the metal</h3>

The stress of the metal is calculated as follows;

σ = F/A = mg/A

where;

A is area of the metal

A = πr²

A = π( 2 x 10⁻³)²

A = 1.257 x 10⁻⁵ m²

σ = (70.5 x 9.8) / (1.257 x 10⁻⁵)

σ = 5.5 x 10⁷ N/m²

<h3>Strain of the metal</h3>

The strain is calculated as follows;

strain = x/L

where;

x is extension

L is original length

strain = (1 x 10⁻³ m) / 2 m

strain = 5 x 10⁻⁴

<h3>Young's modulus of the metal</h3>

E = stress/strain

E = (5.5 x 10⁷ ) / (5 x 10⁻⁴)

E = 1.1 x 10¹¹ N/m²

E = 110 Gpa

The Young's modulus of copper metal is 110 Gpa

Thus, based on the value of the Young's modulus, the strand of the metal is made of copper.

Learn more about Young's modulus here: brainly.com/question/6864866

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aleksklad [387]

Answer:

0.6kg

Explanation:

the unknown here is the mass of the second block

applying the law of the conservation of momentum

m₁v₁ + m₂v₂ = (m₁ + m₂) v₃

where m₁=mass of first block=2.2kg

m₂=mass of colliding block= ?

v₁= velocity of first block=1.2m/s

v₂=velocity of colliding block=4.0m/s

v₃= final velocity of combined block=1.8m/s

applying the formula above

(2.2 × 1.2) + (m₂ × 4) = (2.2 + m₂) × 1.8

2.64 + 4m₂ = 3.96 + 1.8m₂

collecting like terms

4m₂ - 1.8m₂ = 3.96 - 2.64

2.2m₂=1.32

divide both sides by 2.2

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4 0
3 years ago
If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite d
Yuliya22 [10]

Incomplete question as the mass of baseball is missing.I have assume 0.2kg mass of baseball.So complete question is:

A baseball has mass 0.2 kg.If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

Answer:

ΔP=20 kg.m/s

Explanation:

Given data

Mass m=0.2 kg

Initial speed Vi=-44.5m/s

Final speed Vf=55.5 m/s

Required

Change in momentum ΔP

Solution

First we take the batted balls velocity as the final velocity and its direction is the positive direction and we take the pitched balls velocity as the initial velocity and so its direction will be negative direction.So we have:

v_{i}=-44.5m/s\\v_{f}=55.5m/s

Now we need to find the initial momentum

So

P_{1}=m*v_{i}

Substitute the given values

P_{1}=(0.2kg)(-44.5m/s)\\P_{1}=-8.9kg.m/s

Now for final momentum

P_{2}=mv_{f}\\P_{2}=(0.2kg)(55.5m/s)\\P_{2}=11.1kg.m/s

So the change in momentum is given as:

ΔP=P₂-P₁

=[(11.1kg.m/s)-(-8.9kg.m/s)]\\=20kg.m/s

ΔP=20 kg.m/s

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Speed = distance/time

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Speed = 4 m/s

Ms Kasper must run at speed more than 4m/s for her to save the cat.

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