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vova2212 [387]
3 years ago
10

Pollution that is ______ will break down over time. a good example would be______

Physics
1 answer:
marusya05 [52]3 years ago
3 0
Biodegradable         when wood rots 

like if you leave types of paper and wood or cardboard over time it will break down and enrich the soil.

same things with a compost. 
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How would your mass change if you took a trip to the space station? 1. no change in mass 2. decreases; you weigh less. 3. increa
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No chande in mass becouse of the change in gravitational force do not effect in mass
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3 years ago
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HELP ME PLEASE IM DESPERATE Many inland areas around Florida contain extinct marine fossils.
chubhunter [2.5K]

Answer:b

Explanation:

thats what my teacher said

8 0
3 years ago
The block A and attached rod have a combined mass of 50 kg and are confined to move along the guide under the action of the 796-
Luba_88 [7]

Answer:

The bending moment is 459.16 N.m

Explanation:

From the given information;

Let's assume that the angle is 66°

Then, the free body diagram is draw and attached in the file below.

Now, the calculation of the acceleration from the first part of the free body diagram is:

\sum F_x = ma_x \\ \\ 796 - 50(9.81) sin 66=50a \\ \\ 796 - 448.094 = 50 a  \\ \\ a = \dfrac{347.906}{50} \\ \\ a  = 6.96 \ m/s^2

Bending moment M:

From the second part of the diagram:

\sum M_B = mad \\ \\ M - (15 \times 9.81) (1.5) = (25 \times 6.96)(1.5 sin 66) \\ \\ M - 220.725 = 238.435  \\ \\  M = 238.435 + 220.725 \\ \\  \mathbf{M = 459.16 \ N.m}

6 0
3 years ago
What is the minimum energy required to lift an object weighing 200 newtons to a height of 20 meters
IgorC [24]
Potential energy E = mgh

m mass
g gravitational constant
mg = weight (in Newton)
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7 0
3 years ago
An automobile of mass 1300 kg has an initial velocity of 7.20 m/s toward the north and a final velocity of 6.50 m/s toward the w
Svetradugi [14.3K]

Answer

given,

mass of the automobile = 1300 Kg

initial speed of the automobile in north direction= 7.20 j m/s

final speed of the automobile in west direction = -6.50 i m/s

now,

change in momentum

\Delta P = m (v_f - v_i)

\Delta P = 1300\times (-6.50 \hat{i} - 7.20 \hat{j})

\Delta P = 1300\times \sqrt{(-6.50)^2 + (-7.20)^2}

\Delta P = 1300\times 9.7

\Delta P = 12610\ kg.m/s

now, direction calculation

 \theta = tan^{-1}(\dfrac{7.2}{6.5})

 \theta = tan^{-1}(1.1076)

 \theta = 47.92^0

direction of the car is 48° in south west direction.

3 0
4 years ago
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