The volume of 3.40 mol of gas at 33.3 C and 22.2 atm of pressure is 3.85 liter of gas. This problem can be solved by using the PV=nRT or V= nRT/V equation which is the relation between the molar volume, the temperature, and the pressure of gas. In this formula, P is the pressure, R is the universal gas constant ( 0.0821 atm L/mol K), n is the molecule amount, V is the molecular volume, and T is the temperature. The temperature used in this formula must be in Kelvin, therefore we have to convert the Celcius temperature into Kelvin temperature (33.3 C = 306.45 K).
<span>The calculation for the problem above: 3.4*0.0821*306.45/22.2 = 3.85 liter of gas.</span>
Answer:
734.0 grams
Explanation:
Because 16.0 and 855 mL it is 734.0 grams :) hope it helps
D = m / V
1.025 = m / 100,000 mL
m = 1.025 x 100,000
m = 102,500 g
Answer:
6%
Explanation:
Hello, for this case, we assume that the volume of the solution is 1L, thus, the mass is given by using the density as follows:
Now, the mass of the ethanol:
Finally, the by mass percent is:
%
%m=6%
Best regards.
