Bone age : 22,920 years
<h3>Further explanation</h3>
Given
Nt = 2.5 g C-14
No = 40 g
half-life = 5730 years
Required
time of decay
Solution
General formulas used in decay:
t = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
Input the value :
The compression factor based on the information given is 0.083.
<h3>How to calculate the compression factor?</h3>
The way to calculate the compression factor goes this:
V(ideal) = RT/P
= (0.0821 × 250)/15
= 1.368
V(real) will be:
= V(ideal)/12
= 1.368/12 = 0.114
The compression factor will be:
= 1.368/(12 × 1.368)
= 0.083
Therefore, the compression factor is 0.083.
Learn more about compression factor on:
brainly.com/question/24261456
#SPJ12
The answer is hard to give without any information.
One mole of water weighs 18 grams. H₂O is composed of 2H= 2 and 1 0=16 adding gives you 18. number of moles= mass/ Relative Molecular Mass
Therefore, mass= Relative Molecular Mass×number of moles
= 18×5 moles
= 90 grams
2 moles of sodium hydroxide will be needed.
<h3><u>Explanation</u>:</h3>
Sodium hydroxide is a compound which is a base and nitric acid is the acid. The formula of the nitric acid is HNO3 and that of sodium hydroxide is NaOH.
The reaction between them are
NaOH +HNO3 =NaNO3 +H2O.
So here we can see that 1 mole of sodium hydroxide reacts with 1 mole of nitric acid to produce 1 mole of sodium nitrate and 1 mole of water.
So for 2 moles of nitric acid, 2 moles of sodium hydroxide will be required.
