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elena-14-01-66 [18.8K]
3 years ago
12

A 700 kg car is moving at 10 m/s west rear ends a 500 kg car at rest. They both stuck together after the collision and continue

to move. How fast are they both moving together after the collision?
Physics
2 answers:
Fittoniya [83]3 years ago
8 0

Answer:

5.83 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

mu+m'u' = V(m+m')..................... Equation 1

Where m = mass of the first car, m' = mass of the second car, u = initial velocity of the first car, u' = initial velocity of the second car, V = common velocity of both cars after collision

make V the subject of the equation,

V = (mu+m'u')/(m+m')................. Equation 2

Given: m = 700 kg, m' = 500 kg, u = 10 m/s, u' = 0 m/s ( at rest)

Substitute into equation 2

V = (700×10+500×0)/(700+500)

V = 7000/1200

V = 5.83 m/s

nataly862011 [7]3 years ago
6 0

Answer:

v = 5.833\,\frac{m}{s}

Explanation:

The collision is inelastic and can be described by the Principle of Momentum Conservation:

(700\,kg)\cdot (10\,\frac{m}{s} ) + (500\,kg)\cdot (0\,\frac{m}{s} ) = (1200\,kg)\cdot v

The speed after the collision is:

v = 5.833\,\frac{m}{s}

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