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erastova [34]
4 years ago
5

How many protons are in one atom of 37Ar

Chemistry
1 answer:
Archy [21]4 years ago
7 0

There are 18 protons in one atom of ³⁷Ar.

The number 37 is its <em>mass number</em> — the number of <em>protons + neutrons</em>.

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ASAP!
Sav [38]

When a radioactive isotope releases an alpha particle, the atomic number of the atom is decreased by four.

So, the correct answer is B.

Hope this helps,

Davinia.

4 0
3 years ago
All factors that cause an increase in the rate of dissolving have what in common?
Nikitich [7]

Answer:

They increase the attractive forces between the solute and solvent particles.

Explanation:

The dissolution of a solute in a solvent depends on interaction between the solute and the solvent. The more the attractive force and interaction between solute and solvent, the greater the greater the rate of dissolution of the solute in the solvent.

The absence of interaction between solute and solvent molecules means that the substance can not dissolve in that particular solvent. Hence, any factor that enhances solute-solvent interaction will enhance dissolution of a solute in a particular solvent.

3 0
3 years ago
Describe the importance of plaster of paris
mojhsa [17]

Answer:

plaster is important because of the many uses you can make out of plaster

6 0
2 years ago
Which of the following statements about this reaction is true:
Semmy [17]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The Correct statement is ~

  • A. The reaction releases heat

As we can observe, there's heat in product side of the given equation that shows - In the given reaction heat is released making it an exothermic reaction ~

I hope it helps ¡

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6 0
2 years ago
How many atoms of mercury are present in 3.4 cubic centimeters of liquid mercury? the density of mercury is 13.55 g/cc?
maks197457 [2]

Answer:

             1.37 × 10²³ Atoms of Mercury  

Solution:

Step 1: Calculate Mass of Mercury using following formula,

                               Density  =  Mass ÷ Volume

Solving for Mass,

                               Mass  =  Density × Volume

Putting values,

                               Mass  =  13.55 g.cm⁻³ × 3.4 cm³                ∴ 1 cm³ = 1 cc

                               Mass  =  46.07 g

Step 2: Calculating number of Moles using following formula;

                               Moles  =  Mass ÷ M.mass

Putting values,

                               Moles  =  46.07 g ÷ 200.59 g.mol⁻¹

                               Moles  =  0.229 mol

Step 3: Calculating Number of Atoms using following formula;

                               Number of atoms  =  Moles × 6.022 ×10²³

Putting value of moles,

                               Number of Atoms  =  0.229 mol × 6.022 × 10²³

                              Number of Atoms  =  1.37 × 10²³ Atoms of Hg

8 0
3 years ago
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