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4 years ago

How many protons are in one atom of 37Ar

Chemistry

1 answer:

Archy [21]4 years ago

7 0

There are 18 protons in one atom of ³⁷Ar.

The number 37 is its <em>mass number</em> — the number of <em>protons + neutrons</em>.

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Which equation represents a nuclear reaction that an example of an artificial transmutation?

blsea [12.9K]

Answer is: 2) 14/7 N + 4/2 He --> 17/8 O + 1/1 H.

Transmutation is a process that involves a change in the nucleus of an atom. It can be natural or artificial.

This example is the first artificial nuclear transmutation described by Rutherford in 1919.

Artificial transmutation can be expressed by nuclear reaction:

Target Nuclide + Bombardment Particle → New Nuclide + Ejected Particle.

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3 years ago

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Revision has a atoMic number of 37 and a mass number of 85. HIW many protons, neutrons and electrons does an ion of rubidium wit

EleoNora [17]

Answer: 37 protons, 48 neutrons, and 36 electrons.

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3 years ago

Lithium acetate, LiCH3CO2, is a salt formed from the neutralization of the weak acid acetic acid, CH3CO2H, with the strong base

Vesna [10]

Answer : The pH of 0.289 M solution of lithium acetate at $25^oC$ is 9.1

Explanation :

First we have to calculate the value of $K_b$ .

As we know that,

$K_a\times K_b=K_w$

where,

$K_a$ = dissociation constant of an acid = $1.8\times 10^{-5}$

$K_b$ = dissociation constant of a base = ?

$K_w$ = dissociation constant of water = $1\times 10^{-14}$

Now put all the given values in the above expression, we get the dissociation constant of a base.

$1.8\times 10^{-5}\times K_b=1\times 10^{-14}$

$K_b=5.5\times 10^{-10}$

Now we have to calculate the concentration of hydroxide ion.

Formula used :

$[OH^-]=(K_b\times C)^{\frac{1}{2}}$

where,

C is the concentration of solution.

Now put all the given values in this formula, we get:

$[OH^-]=(5.5\times 10^{-10}\times 0.289)^{\frac{1}{2}}$

$[OH^-]=1.3\times 10^{-5}M$

Now we have to calculate the pOH.

$pOH=-\log [OH^-]$

$pOH=-\log (1.3\times 10^{-5})$

$pOH=4.9$

Now we have to calculate the pH.

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-4.9=9.1$

Therefore, the pH of 0.289 M solution of lithium acetate at $25^oC$ is 9.1

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