According to Arrhenius concept a base is one which can donate hydroxide ion in its aqueous solution.
Here NaOH is a base as it can donate OH-.
As NaOH is a strong base it will have very high dissociation constant.
Due to high dissociation constant if will almost completely dissociate into sodium ions and hydroxide ions.
Thus in a solution of NaOH we will expect the following two ions
Na^{+} + OH^{-}[/tex]
Answer:
The mass of 10 cm³of a 0.4 g/dm³ solution of sodium carbonate is 0.004 grams
Explanation:
The question is with regards to density calculations
The density of the given sodium carbonate solution, ρ = 0.4 g/dm³
The volume of the given solution of sodium carbonate, V = 10 cm³ = 0.01 dm³
Therefore, we have;
The mass, "m", of the sodium carbonate in = ρ×V = 0.4 g/dm³ × 0.01 dm³ = 0.004 g
The mass of 10 cm³ (10 cm³ = 0.01 dm³) of a 0.4 g/dm³ solution of sodium carbonate, m = 0.004 g.
