An aptitude test is a systematic means of testing a job candidate's abilities to perform specific tasks and react to a range of different situations. The tests each have a standardised method of administration and scoring. The results are quantified and compared with all other test takers.
Answer:
Acceleration=velocity/time.
=80/2=40m/s^2.
Answer:
Dy = - 0.0789 [m]
Explanation:
The vertical component of the vector can be determined with the sine of the angle.
Dy = 0.250*sin(18.4)
Dy = 0.0789 [m]
As the y-component is pointing downwards the component is negative.
Dy = - 0.0789 [m]
Given:
m = 0.240 kg = 240 g, the mass of O₂
V = 3.10 L = 3.10 x 10⁻³ m³, the volume
Because the molar mass of oxygen is 16, the number of moles of O₂ is
n = (240 g)/(2*16 g/mol) = 7.5 mol
As an ideal gas,
p*V = nRT
or
V = (nRT)/p
where R = 8.314 J/(mol-K)
When
p = 0.910 atm = (0.910 atm) * (101325Pa/atm) = 92205.75 Pa
T = 27 °C = (27 + 273) K = 300 K
then the volume is

V = (0.2029 m³)*(10³ L/m³) = 202.9 L
Answer: 203 liters
Answer:
17 m/s
Explanation:
Using formula a = (v-u) /t
acceleration a = -1.5 m/s2
final velocity v = unknown
initial velocity u = 32 m/s
time t = 10s
-1.5 = (v-32)/10
-15 = v - 32
-15 + 32 = v
v = 17 m/s