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Tanzania [10]
3 years ago
9

Water particles in an ocean wave move in circles. This particle movement causes a wooden raft to...

Physics
2 answers:
34kurt3 years ago
8 0

Answer:

bob up and down in the water.

Explanation:

usatestpre

nikklg [1K]3 years ago
3 0

Answer:

The Answer Is C

Explanation:

C) bob up and down in the water.

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Calculate the Potential Energy of an object that has a mass of 14-kg and is located at a height of 24-m?
inessss [21]
Potential Energy= 24m * 14kg * 9.8N/kg = 3292.8J
4 0
3 years ago
A train starts at rest in a station and accelerates at a constant 0.987 m/s2 for 182 seconds. Then the train decelerates at a co
algol [13]

Answer:

\displaystyle X_T=66.6\ km

Explanation:

<u>Accelerated Motion </u>

When a body changes its speed at a constant rate, i.e. same changes take same times, then it has a constant acceleration. The acceleration can be positive or negative. In the first case, the speed increases, and in the second time, the speed lowers until it eventually stops. The equation for the speed vf at any time t is given by

\displaystyle V_f=V_o+a\ t

where a is the acceleration, and vo is the initial speed .

The train has two different types of motion. It first starts from rest and has a constant acceleration of 0.987 m/s^2 for 182 seconds. Then it brakes with a constant acceleration of -0.321 m/s^2 until it comes to a stop. We need to find the total distance traveled.

The equation for the distance is

\displaystyle X=V_o\ t+\frac{a\ t^2}{2}

Our data is

\displaystyle V_o=0,a=0.987m/s^2,\ t=182\ sec

Let's compute the first distance X1

\displaystyle X_1=0+\frac{0.987\times 182^2}{2}

\displaystyle X_1=16,346.7\ m

Now, we find the speed at the end of the first period of time

\displaystyle V_{f1}=0+0.987\times 182

\displaystyle V_{f1}=179.6\ m/s

That is the speed the train is at the moment it starts to brake. We need to compute the time needed to stop the train, that is, to make vf=0

\displaystyle V_o=179.6,a=-0.321\ m/s^2\ ,V_f=0

\displaystyle t=\frac{v_f-v_o}{a}=\frac{0-179.6}{-0.321}

\displaystyle t=559.5\ sec

Computing the second distance

\displaystyle X_2=179.6\times559.5\ \frac{-0.321\times 559.5^2}{2}

\displaystyle X_2=50,243.2\ m

The total distance is

\displaystyle X_t=x_1+x_2=16,346.7+50,243.2

\displaystyle X_t=66,589.9\ m

\displaystyle \boxed{X_T=66.6\ km}

8 0
3 years ago
A student writes the following script for a scene in a futuristic movie.
Triss [41]
The astronauts hearing the rocket landing is inaccurate. Sound waves can’t travel through a vacuum, meaning a place where there are no air particles. They are mechanical waves and require a medium to travel through. So, because there is no air in space, you can’t hear anything.
8 0
3 years ago
Is this right? Please help me
prohojiy [21]

Answer:

It would be C

Explanation:

The brain operates on two levels, one of them is unconscious.

6 0
2 years ago
Read 2 more answers
Take the following measured gauge (or gage) pressures and convert them to absolute pressures in both kPa and psi units for an am
mamaluj [8]

Answer:

Explanation:

Given

ambient Pressure =98.10 kPa

(a)gauge pressure 152 kPa

we know

Absolute pressure=gauge pressure+Vacuum  Pressure

P_{abs}=152+98.10=250.1 kPa or 36.27 psi

(b)P_{gauge}=67.5 Torr or 8.99 kpa

as 1 Torr is 0.133 kPa

P_{abs}=8.99+98.10=107.09 kPa or 15.53 psi

(c)P_{vaccum}=0.1 bar or 10 kPa

Thus absolute pressure=98.10-10=88.10 kPa or 12.77 psi

as 1 kPa is equal to 0.145 psi

(d)P_{vaccum}=0.84 atm  or 85.113 kPa

as 1 atm is equal to 101.325 kPa

P_{abs}=98.10-85.11=12.99 kPa or 1.88 psi

6 0
3 years ago
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