Increasing the mass attached to a spring will increase it's vibrational period - this is true. Imagine placing an elephant at the end of a bungee cord vs an apple, the apple will recoil faster than the elephant.
An airplane requires a much less force in order to get off the ground than a rocket does, since a rocket needs to exit Earth’s atmosphere.
Planes typically travel at much slower speeds that traditional rockets, as they are faced with varying restrictions that affect how quickly they fly.
Both forms of transportation, although very different in certain aspects, are similar in the fact that they both need to adhere to similar constraints. Although most airplanes aren’t faced with the challenge of exiting the atmosphere, they do need to focus on their fuel, their safety, etc. just as rockets do as well.
The following
are the answers to the questions presented:
a. The joules of energy required to run a 100W light bulb for one day is 8640000J
b. The amount of coals that has to be burned to light that light bulb for one day is 0.96kg
The solution would
be like this for this specific problem:
<span>P=<span>W/s</span>→W=Pt=100W1day <span><span>24h/</span><span>1day </span></span><span><span>3600s/</span><span>1h</span></span>=8640000J</span>
<span>W=<span>30/100</span>wm→m=<span><span>100W/</span><span>30w</span></span>=<span><span>100×8640000J/</span><span>30×30×<span>10in thepowerof6 </span><span>J/<span>kg</span></span></span></span>=0.96kg</span>
<span>I am hoping that
these answers have satisfied your queries and it will be able to help you in
your endeavors, and if you would like, feel free to ask another question.</span>
Answer:
you can see it in the picture
To solve this problem, we must take two important steps. First we will convert all the given units, to international system. Later we will define the torque, which is given as the product between the radius of application of the force and the Force acting on the body. Mathematically the latter is,

Here,
r = Radius
F = Force
Now the units,

Replacing,


Therefore the torque that the muscle produces on the wrist is 