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PtichkaEL [24]
3 years ago
8

Which element has the same number of valence electrons as hydrogen (H)? A. helium (He). . B. oxygen (O). . C. nitrogen (N). . D.

lithium (Li).
Chemistry
2 answers:
velikii [3]3 years ago
7 0

Answer : The correct option is (D) lithium (Li).

Explanation :

Hydrogen is the element which belong to period 1. The atomic number of hydrogen is, 1

The electronic configuration of hydrogen is, 1s^1

The number of valence electrons present in hydrogen is, 1.

(A) Helium is the element which belong to period 1. The atomic number of helium is, 2

The electronic configuration of helium is, 1s^2

The number of valence electrons present in helium is, 2.

(B) Oxygen is the element which belong to period 2. The atomic number of oxygen is, 8

The electronic configuration of oxygen is, 1s^22s^22p^4

The number of valence electrons present in oxygen is, 6.

(C) Nitrogen is the element which belong to period 2. The atomic number of nitrogen is, 7

The electronic configuration of nitrogen is, 1s^22s^22p^3

The number of valence electrons present in nitrogen is, 5.

(D) Lithium is the element which belong to period 2. The atomic number of lithium is, 3

The electronic configuration of lithium is, 1s^22s^1

The number of valence electrons present in lithium is, 1.

From this we conclude that the lithium element has the same number of valence electrons as hydrogen.

Hence, the correct option is (D) lithium (Li).

deff fn [24]3 years ago
4 0
Li is in group 1 so it has same number of valence electrons as hydrogen.
hope it helps.
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How many Liters of space will a 70.0g sample of CO2 occupy?
Tanzania [10]

Answer:

  35.6 liters at STP

Explanation:

The molar mass of carbon dioxide is about 44.01 g/mol. The volume of a mole of ideal gas at STP is 22.4 L, so the volume of 70.0 g will be ...

  (70.0g)/(44.01 g/mol)·(22.4 L/mol) ≈ 35.6 L

5 0
3 years ago
2Fe(s) +3H2SO4(aq) →Fe2(SO4)3(aq) +3H2(g)When 10.3 g of iron are reacted with 14.8 moles of sulfuric acid, what is the percent y
Elden [556K]

Answer:

1040%

Explanation:

To solve this question we must convert the mass of Iron to moles in order to find limiting reactant. With limiting reactant we can find the theoretical moles of hydrogen and theoretical mass:

Percent yield = Actual yield (5.40g) / Theoretical yield * 100

<em>Moles Fe -Molar mass: 55.845g/mol-:</em>

10.3g * (1mol / 55.845g) = 0.184 moles of Fe will react.

For a complete reaction of these moles there are necessaries:

0.184 moles Fe* ( 3 mol H2SO4 / 2 mol Fe) = 0.277 moles H2SO4.

As there are 14.8 moles of the acid, <em>Fe is limiting reasctant.</em>

The moles of H2 produced are:

0.184 moles Fe* ( 3 mol H2 / 2 mol Fe) = 0.277 moles H2

The mass is:

0.277 moles H2 * (2.016g/mol) = 0.558g H2

Percent yield is:

5.40g / 0.558g * 100 = 1040%

It is possible the experiment wasn't performed correctly

7 0
2 years ago
Need help please !!!!
Margaret [11]

Answer:

2p

Explanation:

it has 3 dumbell shapes, hence p

you can't determine the principal quantum number by looking at the shape, however bigger or spread orbital means higher value of n

3 0
2 years ago
Which elements are present in the compound aluminium nitrate?
PSYCHO15rus [73]

Answer:

Aluminum nitrate is a salt composed of aluminum and nitric acid, belonging to a group of reactive chemicals - organic nitrate and nitrite compounds. The nitrate ion is polyatomic, meaning it is composed of two or more ions that are covalently bonded. This ion makes up the conjugate base of nitric acid.

Explanation:

4 0
2 years ago
Read 2 more answers
A solution of malonic acid, H2C3H2O4 , was standardized by titration with 0.1000 M NaOH solution. If 21.17 mL of the NaOH soluti
MrRa [10]

Answer: The molarity of the malonic acid solution is 0.08335 M

Explanation:

H_2C_3H_2O_4 +2NaOH\rightarrow Na_2C_3H_2O_4+2H_2O

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2C_3H_2O_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=12.70mL\\n_2=1\\M_2=0.1000M\\V_2=21.17mL

Putting values in above equation, we get:

2\times M_1\times 12.70=1\times 0.1000\times 21.17\\\\M_1=0.08335M

Thus the molarity of the malonic acid solution is 0.08335 M

5 0
3 years ago
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