A+bi is a complex number

(3+2i)(a+bi)=17+7i
remember
i²=-1
so
expand and solve
a is the ral part
bi is the imaginary part
ok so
if Ac+Be=dc+fe where c=c and e=e then A=d and B=f

(3+2i)(a+bi)=17+7i
expand/distribute/FOIL
3a+2ai+3bi+2bi²=17+7i
3a+2bi+2ai+2bi=17+7i
3a-2b+2ai+2bi=17+7i
real parts are 3a-2b
imaginary is 2ai+2bi
so

3a-2b=17 and
2ai+2bi=7i

we need to solve
2nd equation, divide both sides by i
2a+2b=7
multiply by -1 and add to other equation

3a+2b=17
<u>-2a-2b=-7 +</u>
1a+0b=10
a=10

subsitue
2a+2b=7
2(10)+2b=7
20+2b=7
2b=-13
b=-13/2

the complex number is
10-(13/2)i or
10-6.5i

8 0

2 years ago

Its about ratios, no links<3

frez [133]

1. 35:10

2. 35:45

3.40:50

4. 2:5

And I dont know the rest

8 0

2 years ago

If 55% of the students in a certain college are female and there are 1,452 female students, what is the total number of students

Len [333]

Answer:

So 55% of an unknown number is 1452

Let this unknown number be n

Then 55% of n = 1452

We now solve for n

55% × n = 1452

55/100 × n = 1452

0.55 × n = 1452

n = 1452/0.55

n = 2640

Therefore there are 2640 students in the college

8 0

2 years ago