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Alex787 [66]
3 years ago
6

What is the pressure exerted by 1.0 mol of a gas with temperature of 20 C and a volume of 7.5 L?

Chemistry
1 answer:
Fofino [41]3 years ago
5 0

We have to assume the gas behaves similar to an ideal gas and we can use the ideal gas law equation

PV = nRT

Where

P - pressure

V - volume - 7.5 L

n - number of moles - 1.0 mol

R - universal gas constant - 0.0821 L.atm/mol.K

T - temperature in kelvin

20 degrees celcius + 273 = 293 K

Substituting the values in the equation

P x 7.5 L = 1.0 mol x 0.0821 L.atm/mol.K x 293 K

P = 3.2 atm

The pressure exerted is 3.2 atm

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How long does it take electrons to get from the car battery to the starting motor? Assume the current is 137 A and the electrons
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Answer:

t = 55.79 min

Explanation:

First, the problem is asking for calculate the time that it takes electrons from the battery to the motor.

The general formula to calculate time is:

<em>t = d/V (1)</em>

Where:

d: distance or length

V: speed

Now, we don't have data of speed, but we can know an expression of current density in function of the distance which is the following:

<em>J = n*q*V (2)</em>

Where:

q: charge of the particle (1.6x10^-19 C)

n: number of charge carriers per unit of volume

Current density (J) is actually current per Area so:

<em>J = I/A (3)</em>

Replacing (3) in (2) we have:

I/A = nqV

Solving for V:

<em>V = I/Anq (4)</em>

Finally, if we replace this expression in (1) we have:

<em>t = nqAd / I (5)</em>

Now, the value of n, it's not given but it can be calculated because we have mass density, molar mass and avogadro's number, so this value of "n" can be calculated using the following expression:

<em>n = D * Av / MM (6)</em>

Where:

D: mass density (kg/m³)

Av: avogadro number (6.02x10^23 atom/mol)

MM: molar mass (kg/mol)

Putting the data that we know to calculate n we have:

n = 8960 * 6.02x10^23 / 0.0635

n = 8.49x10^28 atom/m³

Now with the value of n, we can finally calculate the time:

<em>t = nqAd / I </em>

A is the area and it should be in m²: 44.6 mm² / 1x10^6 m = 4.46x10^-5 m²

d is the length in meter: 75.7 cm / 100 cm/m = 0.757 m

so replacing these data in (5):

t = 8.49x10^28 * 1.6x10^-19 * 4.46x10^-5 * 0.757 / 137

t = 3,347.63 s

But the answer is in minute so:

t = 3,347.63 / 60

<em>t = 55.79 min</em>

so the electrons takes 56 min aprox. to go from the car battery to the starting motor.

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