Answer:
<em>C. The electron-withdrawing fluorine atoms pull electron density from the oxygen in trifluoroacetate. The negative charge is more stabilized in trifluoroacetate by this effect.</em>
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Explanation:
<em>The structures of trifluoroacetate and acetic acid are both shown in the image attached.</em>
<em>The trifluoroacetate anion (CF3CO2-), just like the acetate anion has in the middle, two oxygen atoms.</em>
<em>However, in the trifluoroacetate anion, there are also three electronegative fluorine atoms attached to the nearby carbon atom attached to the carbonyl, and these pull some electron density through the sigma bonding network away from the oxygen atoms, thereby spreading out the negative charge further. This effect, called the "inductive effect" stabilizes the anion formed,the trifouoroacetate anion is thus more stabilized than the acetate anion.</em>
<em>Hence, trifluoroacetic acid is a stronger acid than acetic acid, having a pKa of -0.18.</em>
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<u><em>Hope this helps!</em></u>
<u><em>Please mark brainliest!</em></u>
Even though the numbers are in scientific notation, they are still just numbers. Essentially the question is as simple as "An apple weighs an ounce, how much do 35 apples weigh?". So all you have to do is multiply.
3.25 x
x 6.0 x
= 195
<h3>
Answer:</h3>
Trough
<h3>
Explanation:</h3>
We need to answer the following questions
What is a wave?
- A wave refers to a transmission of a disturbance from one point to another. It involves transfer of energy from the source to other points.
What are the major types of wave?
- Waves may be classified as longitudinal waves or transverse wave based on the vibration of particles relative to the direction of transmission.
What is a transverse wave?
- A transverse wave is a wave in which the vibration of particles is perpendicular to the direction of transmission of the wave.
- This type of wave contains highest points known as crests and lowest points known as troughs.
Answer:
1 & 4
Explanation:
just got it right on edge
The mole fraction of solute in a 3.87 m aqueous solution is 0.0697
<h3>
calculation</h3>
molality = moles of the solute/Kg of the solvent
3.87 m dissolve in 1 Kg of water= 1000g
find the moles of water= mass/molar mass
that is 1000 g/ 18 g/mol= 55.56 moles
mole of solute = 3.87 moles
mole fraction is = moles of solute/moles of solvent
that is 3.87/ 55.56 = 0.0697
