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AnnyKZ [126]
3 years ago
7

: A small block with mass 0.130 kg is attached to a string passing through a hole in a frictionless, horizontal surface. The blo

ck is originally revolving in a circle with a radius of 0.800 m about the hole with a tangential speed of 4.00 m/s. The string is then pulled slowly from below, shortening the radius of the circle in which the block revolves. The breaking strength of the string is 30.0 N. What is the radius of the circle when the string breaks
Physics
1 answer:
LenKa [72]3 years ago
6 0

Answer:

r = 0.0173 m = 1.73 cm

Explanation:

Here, the centripetal force of the block will be providing the required breaking tension in the string:

Tension = Centripetal Force\\T = F_c\\\\T = \frac{mv^2}{r} \\\\r = \frac{mv^2}{T}\\

where,

r = radius = ?

m = mass of block = 0.13 kg

v = tangential spee of block = 4 m/s

T = Breaking Strength = 30 N

Therefore,

r = \frac{(0.13\ kg)(4\ m/s)^2}{30\ N}

<u>r = 0.0173 m = 1.73 cm</u>

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A 10 gauge copper wire carries a current of 15 A. Assuming one free electron per copper atom, calculate the drift velocity of the electrons. (The cross-sectional area of a 10-gauge wire is 5.261 mm².)

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molar mass of copper, M = 63.5 x 10⁻³kg/mol

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The number of copper atoms, N, per cubic meter is given by;

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<em>Substitute the values of Nₐ, ρ and M into equation (ii) as follows;</em>

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v = \frac{I}{nqA}

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v = 3.22 x 10⁻⁴ m/s

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