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Len [333]
3 years ago
11

For the same reaction above, if 32 grams of AlCl3 is combined with excess AgNO3, how many grams of AgCl can be made

Chemistry
1 answer:
ella [17]3 years ago
8 0

Answer:

103.2 g of AgCl can be made in the reaction

Explanation:

We state the reaction to analyse the problem:

AlCl₃ + 3AgNO₃ →  3AgCl  +  Al(NO₃)₃

We convert the mass of chloride to moles:

32 g . 1mol/ 133.34g = 0.240 moles

Ratio is 1:3. See the stoichiometry

1 mol of aluminum chloride can produce 3 moles of AgCl

Then, 0.240 will produce (0.240 . 3)/1= 0.720 moles.

We convert the moles to mass: 0.720 mol . 143.32g/1mol = 103.2 g

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3 years ago
2Fe(OH)3 Fe2O3+3H2O how many grams of Fe2O3 are produced if 10.7 grams of Fe (OH)3 react in this way
sasho [114]

Answer: 7.98 grams of Fe_2O_3 are produced if 10.7 grams of Fe(OH)_3 are reacted.

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)  

Putting values in equation 1, we get:

\text{Moles of} Fe(OH)_3=\frac{10.7g}{106.87g/mol}=0.100mol  

The chemical equation for the reaction is

2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O

By Stoichiometry of the reaction:

2 moles of Fe(OH)_3 produce = 1 mole of Fe_2O_3

So, 0.100 moles of Fe(OH)_3 produce= \frac{1}{2}\times 0.100=0.05mol of Fe_2O_3  

Mass of Fe_2O_3 =moles\times {\text{Molar Mass}}=0.05mol\times 159.69g/mol=7.98g  

Hence 7.98 grams of Fe_2O_3 are produced if 10.7 grams of Fe(OH)_3 are reacted.

3 0
2 years ago
4 NH3 + 6 NO → 5 N2 + 6 H2O How many moles of NH3 are necessary to produce 0.824 mol N2?
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x=0.824*4/5=0.6592 mol
6 0
3 years ago
Lithium iodide has a lattice energy of −7.3×102kJ/mol and a heat of hydration of −793kJ/mol. Find the heat of solution for lithi
Anna007 [38]
Delta H of solution = -Lattice Energy + Hydration 
<span>Delta H of solution=- (-730)+(-793) </span>
<span>Delta H of solution= -63kJ/mol </span>

<span>Now we find moles of LiI: </span>
<span>10gLiI/133.85g=.075moles </span>
<span>multiply moles to the delta H of solution to cross cancel moles. .75moles x -64kJ/mol =4.7</span>
7 0
3 years ago
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