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Elis [28]
3 years ago
13

In order to control bacterial infections and/or food poisoning, the FDA (Food and Drug Administration) has approved the use of n

uclear energy to control pathogens and extend shelf life of refrigerated and frozen uncooked meat. Which nuclear energy application would be most useful for this situation?
Physics
2 answers:
ololo11 [35]3 years ago
8 0

Answer: Irradiation

Explanation: Irradiation is the process by which the food or the package is first exposed to the ionizing radiation.

The radiations like gamma rays, x-rays or electron beam are exposed to the food which increases the shelf life of the food by killing the harmful bacteria in it or by preventing the growth of harmful bacteria on the food.

It basically aids in killing the bacteria that causes the food spoilage.

Lelechka [254]3 years ago
4 0

The answer is food irradiation. This involves the brief exposure of food to gamma rays or X-rays to kill pathogens that may contribute to food spoilage. This increases the shelf-life of the food. Gamma rays and X-rays emanate from nuclear decay of radioactive materials such as uranium..

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The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pres
12345 [234]

Answer:0.0704 kg

Explanation:

Given

initial Absolute pressure(P_1)=210+101.325=311.325

T_1=25^{\circ}\approx 298 K

V=0.025 m^3

T_2=50^{\circ}\approx 323 K

as the volume remains constant therefore

\frac{P_1}{T_1}=\frac{P_2}{T_2}

\frac{311.325}{298}=\frac{P_2}{323}

P_2=337.44 KPa

therefore Gauge pressure is 337.44-101.325=236.117 KPa

Initial mass m_1=\frac{P_1V}{RT_1}=\frac{311.325\times 0.025}{0.0287\times 298}

m_1=0.91 kg

Final mass m_2=\frac{P_2V}{RT_2}=\frac{311.325\times 0.025}{0.0287\times 323}

m_2=0.839

Therefore m_1-m_2=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back

4 0
3 years ago
An arrow is moving at 35 m/s and travels for 5 seconds. how far did the arrow travel?
pashok25 [27]
The answer is 175 meters
8 0
3 years ago
Holden is trying to determine the velocity of his race car. He went 20 meters east, turned around, and went 40 meters west. His
Ludmilka [50]

Answer:

12 m/s west

Explanation:

4 0
3 years ago
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Star A and Star B have measured stellar parallax of 1.0 arc second and 0.75 arc second, respectively. Which star is closer? How
zhuklara [117]

Answer:

Star A is closer than Star B

Explanation:

As we know that in parallax method of distance measurement the angle subtended by the star when it covers a distance of one Parsec arc length, it is known as parallax angle

Here we can say

angle = \frac{1 Parsec}{distance}

so we have

distance = \frac{1 Parsec}{angle}

so here we have

angle subtended by Star A = 1 arc sec

angle subtended by star B = 0.75 arc sec

now we have

distance for star A is given as

d_a = \frac{1 Parsec}{1} = 1 Parsec

distance of star B is given as

d_b = \frac{1 Parsec}{0.75} = 1.33 Parsec

So star A is closer than star B

7 0
3 years ago
A 300-n force acts on a 25-kg object. the acceleration of the object is?
Over [174]
To solve the answer use the equation: a = fnet / m

a = 300 N / 25 kg

300 N / 25 kg = 12m/s

The acceleration of the object is 12m/s

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