Given that
Work = 600,000 J ,
distance(S) = 500 m ,
mass (m) = 250 Kg ,
Determine the velocity of car (v) = ?
We know that,
Work = Force × distance
=> Force = Work ÷ distance
= 600,000 ÷ 500
= 500 N .
Also Force F = m.a ; from Newtons II law
500 = 250 × a
a = 2 m/s.
<em>Final Velocity from the given formula </em>
V² = u² + 2.a.s
= 0 + 2 × 2 × 500
= \sqrt{2000}
<em> v = 44.7 m/s</em>
90.9 is the velocity of an airplane
Answer:
Rectilinear propagation describes the tendency of electromagnetic waves to travel in a straight line. Light does not deviate when travelling through a homogeneous medium, which has the same refractive index throughout; otherwise, light suffers refraction.
The elastic potential energy stored in a spring is given by:
![E=\frac{1}{2}kx^2](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B2%7Dkx%5E2)
where k is the spring constant, and x=0.5 is the compression of the spring. Re-arranging the formula and using E=5 J, we find the spring constant:
![k=\frac{2E}{x^2}=\frac{2(5 J)}{(0.5 m)^2}=40 N/m](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2E%7D%7Bx%5E2%7D%3D%5Cfrac%7B2%285%20J%29%7D%7B%280.5%20m%29%5E2%7D%3D40%20N%2Fm)