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stiks02 [169]
4 years ago
7

The ratio of output force to input force of a machine it its

Physics
2 answers:
GarryVolchara [31]4 years ago
7 0
Mechanical advantage is the ratio of output force to input force of a machine.

hope this helps and have a great day :)

const2013 [10]4 years ago
4 0

Answer:

Mechanical Advantage (MA)

Explanation:

The Mechanical Advantage (MA) of a machine is defined as:

MA= \frac{F_{out}}{F_{in}}

where

F_{out} is the output force

F_{in} is the input force

Machines are used as force multiplier, which means that they are able to produce an output force which is greater than the input force (and example of machine is the lever). Therefore, the MA of a machine represents the "multiplication factor" of the input force: for instance, if a machine has a MA of 5, it means that the output force is 5 times the force applied in input.

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natulia [17]
D hope it helps you
7 0
3 years ago
The total resistance of a 15-ohm, an 65-ohm and a 35-ohm resistor connected in parallel ​
yanalaym [24]

Answer:

I think its 9.0397 Ohms

Explanation:

take the reciprocal of all the resistances: 1/15, 1/65, 1/35

then add them: = 151/1365

then reciprocal the answer: =1365/151

And chuck it on a calculator: =9.04 Ohms

I think this is right but I'm not entirely sure. Tell me if I'm right by the way!

3 0
3 years ago
A circular rod has a radius of curvature R = 9.09 cm and a uniformly distributed positive charge Q = 6.49 pC and subtends an ang
Digiron [165]

Answer:

E = 1.19 N/C

Explanation:

Let's first determine the length of the arc which can be given as:

L= Rθ

where:

L = length of the arc

R = radius of curvature

θ = angle in radius

L = (9.09×10⁻²m)(2.59)

L = (0.0909)(2.59)

L = 0.235431 m

Then, the magnitude of electric field that Q produces at the center of curvature can be calculated by using the formula:

E= \frac{\lambda}{4 \pi E_oR}[sin\frac{\theta}{2}-sin(-\frac{\theta}{2})]

E= \frac{\lambda}{4 \pi E_oR}[sin\frac{\theta}{2}+sin(\frac{\theta}{2})]

E= \frac{2\lambda}{4 \pi E_oR}[sin\frac{\theta}{2}]

Since \lambda = \frac{Q}{L}

where;

L = length

Q = charge

λ =  density of the charge;

then substituting \frac{Q}{L} for λ, we have :

E= \frac{2(\frac{Q}{L})}{4 \pi E_oR}[sin\frac{\theta}{2}]

E= \frac{2Q[sin\frac{\theta}{2}]}{4 \pi E_oLR}

substituting our given parameter; we have:

E= \frac{2(6.26*10^{-12}C)[sin\frac{2.59rad}{2}]}{4 \pi (8.85*10^{-12}C^2/N.m^2)(0.235431)(0.0909)}

E = 1.1889 N/C

E = 1.19 N/C

∴ the magnitude of the electric field that Q produces at the center of curvature = 1.19 N/C

4 0
3 years ago
1. What types of elements does an ionic bond occur between?
sweet [91]

Answer:

Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions.

Explanation:

6 0
4 years ago
A commuter train travels from the airport for half an hour at 110 km/hr until it reaches the
nikklg [1K]

Answer:

it would be 10km

Explanation:

because that reaches max height before it falls stupid

7 0
3 years ago
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