Answer:
change in entropy is 3.3034 ×
Explanation:
give data
thermal energy Q = 155 J
temperature T = 340 K
to find out
change in entropy
solution
we know change in entropy formula that is
change in entropy = Q / ( K×T ) ..............1
here K is boltzmann constant that is 1.38 × kg-m²/s²
put these value in equation 1 we get
change in entropy = Q / ( K × T )
change in entropy = 155 / ( 1.38 × × 340 )
change in entropy = 3.3034 ×
so change in entropy is 3.3034 ×
<span>A simple harmonic oscillator executes motion whose amplitude </span>
Answer:
(a) 2800 J
(b) 31.28 %
Explanation:
Heat intake, Q1 = 8950 J
Heat discard, Q2 = 6150 J
(a) Work = intake heat energy - discarded heat energy
W = Q1 - Q2 = 8950 - 6150 = 2800 J
(b) Efficiency = 1 - Q2 / Q1
Efficiency = 1 - (6150 / 8950) = 0.3128 = 31.28%
Answer:
1.37 ×10^-3 T
Explanation:
From;
B= μnI
μ = 4π x 10-7 N/A2
n= number of turns /length of wire = 1700/0.75 = 2266.67
I= 0.48 A
Hence;
B= 4π x 10^-7 × 2266.67 ×0.48
B= 1.37 ×10^-3 T