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irga5000 [103]
3 years ago
15

Is a scalene triangle a right triangle

Chemistry
1 answer:
anygoal [31]3 years ago
8 0

A scalene triangle can be a right triangle, depending on if one side of the triangle is equal to 90 degrees.

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The region in which an electron is likely to be found is known as a(n) ____________.
Zinaida [17]

Answer:

orbital

Explanation:

electrons are found in an orbital

3 0
3 years ago
What is the element presented, in this compound?
DerKrebs [107]

compound name compound formula elements present

water H2O hydrogen (H) and oxygen (O)

ammonia NH3 nitrogen (N) and hydrogen (H)

carbon monoxide CO carbon (C) and oxygen (O)

carbon dioxide CO2 carbon (C) and oxygen (O)

4 0
3 years ago
Read 2 more answers
Given the law of conservation of energy, what happens when a 200°C iron bar is placed in thermal contact with a 30°C block of wo
kozerog [31]

Answer:

The correct answer is A Energy leaves the iron bar and enters the wood until the temperature are equal.

Explanation:

According to the law of conservation of energy or the first law thermodynamics energy neither be created nor destroyed, energy is transferred from one form to another form.

        Here iron bar is placed in wood block energy is transferred from iron bar to wood until the temperatures are equal.

7 0
3 years ago
An electric range burner weighing 699.0 grams is turned off after reaching a temperature of 482.0°C, and is allowed to cool down
jasenka [17]

Answer:

0.42 J/gºC

Explanation:

We'll begin by calculating the heat energy used to heat up the water. This can be obtained as follow:

Mass (M) of water = 560 g

Initial temperature (T₁) = 22.7 °C

Final temperature (T₂) = 80.3 °C.

Specific heat capacity (C) of water = 4.18 J/gºC

Heat (Q) absorbed =?

Q = MC(T₂ – T₁)

Q = 560 × 4.18 (80.3 – 22.7)

Q = 2340.8 × 57.6

Q = 134830.08 J

Finally, we shall determine the specific heat capacity of the burner. This can be obtained as follow:

Mass (M) of burner = 699 g

Initial temperature (T₁) = 482.0°C

Final temperature (T₂) = 22.7 °C

Heat (Q) evolved = – 134830.08 J

Specific heat capacity (C) of the burner =?

Q = MC(T₂ – T₁)

–134830.08 = 699 × C (22.7 – 482.0)

–134830.08 = 699 × C × –459.3

–134830.08 = –321050.7 × C

Divide both side by –321050.7

C = –134830.08 / –321050.7

C = 0.42 J/gºC

Therefore, the specific heat capacity of the burner is 0.42 J/gºC

8 0
3 years ago
When a 10 mL graduated cylinder is filled to the 10 mL mark, the mass of the water was measured to be 10.085 g at 20ºC. If the d
Arte-miy333 [17]
The percentage error is the error of the measured value to the true value. To find he percent error, the equation is as follows:

Percent error = |Measured Value - True Value|/True Value  * 100
The || is needed to get the absolute value of the difference. Substituting the values,

Percent error = |(10.085 g/10 mL) - 0.9975 g/mL|/<span>0.9975 g/mL  * 100
</span><em>Percent error = 1.1% </em>
8 0
3 years ago
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