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azamat
4 years ago
11

L 10. A car with a mass of 2,000 kilograms is moving around a circular curve at a uniform velocity of 25 meters per second. The

curve has a radius of 80 meters. What is the centripetal force on the car?
Physics
1 answer:
garri49 [273]4 years ago
3 0
Centripetal Force, F = mv²/r

Where m = mass in kg, v = velocity in m/s and r = radius of curvature in m.

Centripetal Force, F = 2000 * 25² / 80.    Use your calculator.

                           F = 15 625 N.
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The number of waves that pass a given point in a second is___.
Kisachek [45]

Answer:

Frequency

Explanation:

The frequency ( ) of a wave is the number of waves passing a point in a certain time.

5 0
3 years ago
At an altitude of 5000 m the rocket's acceleration has increased to 6.9 m/s2 . What mass of fuel has it burned?
sergey [27]

1) Initial upward acceleration: 6.0 m/s^2

2) Mass of burned fuel: 0.10\cdot 10^4 kg

Explanation:

1)

There are two forces acting on the rocket at the beginning:

- The force of gravity, of magnitude F_g = mg, in the downward direction, where

m=1.9\cdot 10^4 kg is the rocket's mass

g=9.8 m/s^2 is the acceleration of gravity

- The thrust of the motor, T, in the upward direction, of magnitude

T=3.0\cdot 10^5 N

According to Newton's second law of motion, the net force on the rocket must be equal to the product between its mass and its acceleration, so we can write:

T-mg=ma (1)

where a is the acceleration of the rocket.

Solving for a, we find the initial acceleration:

a=\frac{T-mg}{m}=\frac{3.0\cdot 10^5-(1.9\cdot 10^4)(9.8)}{1.9\cdot 10^4}=6.0 m/s^2

2)

When the rocket reaches an altitude of 5000 m, its acceleration has increased to

a'=6.9 m/s^2

The reason for this increase is that the mass of the rocket has decreased, because the rocket has burned some fuel.

We can therefore rewrite eq.(1) as

T-m'g=m'a'

where

m' is the new mass of the rocket

Re-arranging the equation and solving for m', we find

m'=\frac{T}{g+a}=\frac{3.0\cdot 10^5}{9.8+6.9}=1.8\cdot 10^4 kg

And since the initial mass of the rocket was

m=1.9 \cdot 10^4 kg

This means that the mass of fuel burned is

\Delta m = m-m'=1.9\cdot 10^4 - 1.80\cdot 10^4 = 0.10\cdot 10^4 kg

3 0
3 years ago
Does anyone know the answer to this?
sweet-ann [11.9K]
Disclaimer: I just answered this, here is the answer again!
*Used copy paste from my own answer as it is a repeated question, no copied work*

3. A
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4. A
This is another direct linear relation as P=IV.
5. D
The relation between P, R, and V is P=, so P is inversely proportional to R.
6.B
The relation between P,I, and R is , so P is directly proportional to the square of I.

Please note that y:x relations are always straight lines while  relations are parabolic lines.

Hope this helps!
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ahrayia [7]

G2V

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The answer is (C)= zero but that it is swirling rapidly in all directions.
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