Question

Copper (II) sulfate (CuSO4) forms a hydrate. If 4.56 g of the hydrate yields 2.92 g of anhydrous CuSO4, what is the correct name for the hydrate?

Answer 1

Answer:

the   formula    hydrate  salt  =  CuSO4.5H20     which  is  known  as  copper  (ii)    sulfate  pentahydrate

Answer 2

 The  correct   name  for  the  hydrate     salt  is    calculated  as  follows

calculate  the  mass  of  water =mass  of  hydrated  salt-  mass  of  anhydrous  salt

4.56-2.92=1.64g
mass  of  anhydrous    salt (CuSo4)=  2.92g

calculate  the  mole  of     water  and  anhydrous  salt
that  is
moles =mass/molar  mass
moles of  water  = 1.64g/18g/mol= 0.0911  moles

moles  of  CUSO4 =2.92g/  159.5  g/mol=0.0183  moles

find  the  moles ratio  by  dividing   with the  smallest  moles  that  is   0.0183  moles

for  H20 =  0.0911/0.0183=  5
CuSO4 = 0.0183/0.0183=1

the   formula    hydrate  salt  =  CuSO4.5H20     which  is  known  as  copper  (ii)    sulfate  pentahydrate