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dybincka [34]
4 years ago
9

A solution containing an equal number of hydrogen ions and hydroxide ions isA. basicB. alkalineC. acidicD. neutral.

Chemistry
1 answer:
Goryan [66]4 years ago
5 0

Answer:

Neutral (Option D)

Explanation:

[H₃O⁺] = [OH⁻]  → Neutral solution   pH = 7

[H₃O⁺] < [OH⁻]  → Alkaline / Basic solution   pH > 7

[H₃O⁺] > [OH⁻] → Acidic solution   pH < 7

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how did the gross colors (continuous spectrum imparted to the flame by the metal ion solutions compare with the individual spect
Anna35 [415]

The gross colors can be imparted to the flame by the metal ion solutions .

1.To serve as an excitation source, turn on a Bunsen burner.

2. Perform flame tests on the chloride solutions of Li+, Na+, K+, Ca2+, Sr2+, and Ba2+ as instructed by your lab instructor. Wearing the unique glass blower glasses, take note of the obscene hue that each ion contributes to the flame. With one exception: in order to view the sodium flame, you must remove the special glasses that suppress sodium emissions.

3. Obtain two unidentified answers and note their numerical values. Using the ugly hue the solution gives the flame as a guide, identify the metal ions that are present.

One of the six ions you tested will make up the particle.

To know more about continuous spectrum, please refer:

brainly.com/question/28032005

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7 0
1 year ago
When a forest burns and all that's left is some ash,
dalvyx [7]

Answer:

C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + H₂O

Explanation:

When a forest burns and all that's left is some ash,  most of the mass of the trees go to the atmosphere, in the form of carbon dioxide.

In a total combustion process of organic matter,<em> the two molecules produced are carbon dioxide and water. </em>(CO₂ and H₂O)

The equation for the combustion of glucose is:

C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + H₂O

8 0
3 years ago
Read 2 more answers
Calculate how many grams of BeCl2 are required to produce 0.52 grams of MnCl2
Leokris [45]

Answer:

65.0cp

Explanation:

7 0
3 years ago
f 23.2 grams of an aqueous solution of nickel(II) iodide, NiI2, contains 5.47 grams of nickel(II) iodide, what is the percentage
Dahasolnce [82]

Answer:

the percentage by mass of Nickel(II) iodide = 23.58%

Explanation:

% by mass of solute = (mass of solute/mass of solution) x 100%

% by mass of NiI2 = (mass of NiI2/mass of solution) x 100%

% by mass of NiI2 = (5.47 grams/23.2 grams) x 100% = 23.58% m/m

3 0
3 years ago
What is the concentration of chloride ions in a solution formed by mixing 150. mL of a 1.50 M NaCl solution with 250. mL of a 0.
joja [24]
Here, we apply a mass balance:
Moles of chloride ions in final solution = sum of moles of chloride ions in added solutions

We must also not that each mole of sodium chloride will release one mole of chloride ions, while each mole of magnesium chloride will release two moles of chloride ions.
Moles = concentration * volume
Moles in final solution = moles in NaCl solution + moles in MgCl₂ solution
C * (150 + 250) = 1.5 * 150 + 2 * 0.75 * 250
C = 1.5 M

The final concentration is 1.5 M
4 0
3 years ago
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