The gross colors can be imparted to the flame by the metal ion solutions .
1.To serve as an excitation source, turn on a Bunsen burner.
2. Perform flame tests on the chloride solutions of Li+, Na+, K+, Ca2+, Sr2+, and Ba2+ as instructed by your lab instructor. Wearing the unique glass blower glasses, take note of the obscene hue that each ion contributes to the flame. With one exception: in order to view the sodium flame, you must remove the special glasses that suppress sodium emissions.
3. Obtain two unidentified answers and note their numerical values. Using the ugly hue the solution gives the flame as a guide, identify the metal ions that are present.
One of the six ions you tested will make up the particle.
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Answer:
C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + H₂O
Explanation:
When a forest burns and all that's left is some ash, most of the mass of the trees go to the atmosphere, in the form of carbon dioxide.
In a total combustion process of organic matter,<em> the two molecules produced are carbon dioxide and water. </em>(CO₂ and H₂O)
The equation for the combustion of glucose is:
C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + H₂O
Answer:
the percentage by mass of Nickel(II) iodide = 23.58%
Explanation:
% by mass of solute = (mass of solute/mass of solution) x 100%
% by mass of NiI2 = (mass of NiI2/mass of solution) x 100%
% by mass of NiI2 = (5.47 grams/23.2 grams) x 100% = 23.58% m/m
Here, we apply a mass balance:
Moles of chloride ions in final solution = sum of moles of chloride ions in added solutions
We must also not that each mole of sodium chloride will release one mole of chloride ions, while each mole of magnesium chloride will release two moles of chloride ions.
Moles = concentration * volume
Moles in final solution = moles in NaCl solution + moles in MgCl₂ solution
C * (150 + 250) = 1.5 * 150 + 2 * 0.75 * 250
C = 1.5 M
The final concentration is 1.5 M
