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Dmitriy789 [7]
3 years ago
13

What is the nuclear binding energy in joules for an atom of lithium?

Chemistry
1 answer:
deff fn [24]3 years ago
5 0
Answer:

<span>5.1012⋅<span>10<span>−12</span></span>J t</span>he idea here is that you need to use the mass of a single proton and the mass of a single neutron to calculate the mass of a lithium-6 nucleus, then use the measured value to find its mass defect.

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3 years ago
In which of the following does the land being moved contin approximately 60% water
sp2606 [1]

Answer:

C

Explanation:

The answer is C because only that amount can move

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Read 2 more answers
The names and chemical formulae of some chemical compounds are written in the first two columns of the table below. Each compoun
charle [14.2K]

Answer:

See below  

Explanation:

<u>          Name         </u>  <u>Formula </u>      <u>       Major species     </u> <u>  </u>        

Zinc iodide              ZnI₂            H₂O(ℓ),  I⁻(aq), Zn²⁺(aq),  

Nitrogen(I) oxide     N₂O           H₂O(ℓ),  N₂O(aq)

Sodium nitrite         NaNO₂      H₂O(ℓ),  Na⁺(aq), NO₂⁻(aq)

Glucose                   C₆H₁₂O₆    H₂O(ℓ),  C₆H₁₂O₆(aq)

Nickel(II) iodide       NiI₂            H₂O(ℓ),  I⁻(aq), Ni²⁺(aq)

  • Glucose and nitrogen(I) oxide are covalent compounds. They do not dissociate in solution.
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6 0
3 years ago
Suppose you need of Grade 70 tow chain, which has a diameter of and weighs , to tow a car. How would you calculate the mass of t
BabaBlast [244]

Answer: check explanation

Explanation:

In this question we are to find mass. In order to calculate the Mass, We need the values of two parameters, that is, the values given for the grade tow chain, and the value given for the mass per length.

Assuming the mass per length is 3 Kilogram per metre(kg/m) and the grade 70 tow chain length is 5 metre(m).

Therefore, the formula for calculating mass of the chain is given below;

Mass of the chain= mass per unit length(kg/m) × length ---------------------------------------------------------------------------------------------------------------------(1).

Mass of the chain= 3 kg/m × 5 m.

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7 0
3 years ago
To what volume in millimeters must 50.0 mL of 18.0 M H2SO4 be diluted to obtain 4.35 M H2SO4?
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We know that to relate solutions of with the factors of molarity and volume, we can use the equation: M_{1}  V_{1} = M_{2}  V_{2}

**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.

So now we can assign values to these variables. Let us say that the 18 M H_{2}  SO_{4} is the left side of the equation. Then we have:

(18 M)(0.050 L)=(4.35M) V_{2}

We can then solve for V_{2}:

V_{2}= \frac{(18M)(0.05L)}{4.35M} and V_{2} =0.21 L or 210 mL

We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.


7 0
3 years ago
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