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4 years ago

Describe light with respect to its speed and its dual nature as both a wave and a particle.

Chemistry

1 answer:

Sedbober [7]4 years ago

5 0

Answer:

Scientists have been debating over light being a wave or particle since its recognition.

Sir Issac Newton discovered that light had frequency and other properties. Newton described light to be a particle because it created shadows which were sharp and very clear.

Francesco Maria Grimaldi, claimed that light was a wave. This was because this scientist observed the diffraction of light and hence, claimed light to be a type of wave.

The speed of light is 299 792 458 m / s. Nothing can travel faster than light.

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Which generates waves that are capable of traveling through a vacuum?

CaHeK987 [17]

Answer:

Light bulbs

Explanation:

light waves are electromagnetic waves which can travel through a vacuum

7 0

3 years ago

Which of the protist is the most complex organism ?

Evgen [1.6K]

Which of the protist is the most complex organism ?

A) paramecium

B) amoeba 

C) Euglena

D) Volvox

7 0

3 years ago

Which of the following is true about the law of consevation

Mkey [24]

Answer:

just look it up

Explanation:

4 0

3 years ago

How do you find the limiting reactant if 2.50 mol copper and 5.50 mol silver nitrate react by single displacement?

Crank

The limiting reagent is Copper (Cu).

Explanation:

To identify the limiting reactant., first balance the reaction.

The balanced equation is:

Cu + 2AgNO3 -----> Cu(NO3)2 + 2Ag

To find the limiting reactant, take the amount of initial substance and find the number of moles of one of the products. The reactant that gives a product with the least number of moles, is the limiting reactant

$5.50 mol Cu \times (\frac{1.00 mol Cu}{2.00 mol AgNO3} )$ = 2.75 mol Cu.

Since there are only 2.50 mol Cu, copper is the limiting reactant, because, with that quantity of copper, only 2.50 mol AgNO3 will be reacted.

6 0

3 years ago

Menthol, the substance we can smell in mentholated cough drops, is composed of c, h, and o. a 9.045×10−2 −mg sample of menthol i

Ket [755]

Answer:

Empirical Formula = C₁₀H₂₀O

Solution:

Data Given:

Mass of Menthol = 9.045 × 10⁻² mg = 9.045 × 10⁻⁵ g

Mass of CO₂ = 0.2546 mg = 0.0002546 g

Mass of H₂O = 0.1043 mg = 0.0001043 g

Step 1: Calculate %age of Elements as;

%C = (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

%C = (0.0002546 ÷ 9.045 × 10⁻⁵) × (12 ÷ 44) × 100

%C = (2.814) × (12 ÷ 44) × 100

%C = 2.814 × 0.2727 × 100

%C = 76.73 %

%H = (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

%H = (0.0001043 ÷ 9.045 × 10⁻⁵) × (2.02 ÷ 18.02) × 100

%H = (1.153) × (2.02 ÷ 18.02) × 100

%H = 1.153 × 0.1120 × 100

%H = 12.91 %

%O = 100% - (%C + %H)

%O = 100% - (76.73% + 12.91%)

%O = 100% - 89.64%

%O = 10.36 %

Step 2: Calculate Moles of each Element;

Moles of C = %C ÷ At.Mass of C

Moles of C = 76.73 ÷ 12.01

Moles of C = 6.3888 mol

Moles of H = %H ÷ At.Mass of H

Moles of H = 12.91 ÷ 1.01

Moles of H = 12.7821 mol

Moles of O = %O ÷ At.Mass of O

Moles of O = 10.36 ÷ 16.0

Moles of O = 0.6475 mol

Step 3: Find out mole ratio and simplify it;

C H O

6.3888 12.7821 0.6475

6.3888/0.6475 12.7821/0.6475 0.6475/0.6475

9.86 19.74 1

≈ 10 ≈ 20 1

Result:

Empirical Formula = C₁₀H₂₀O₁

8 0

3 years ago