2 years ago

If a 273g of a material displaced 26 mL of water, what is its density?

Chemistry

1 answer:

STatiana [176]2 years ago

4 0

The density would be 10.5

You might be interested in

Is a cube of salt being crushed before being stirred into water a physical or chemical change

Olin [163]

By crushing the salt, you are performing a physical change because you aren't altering the chemical makeup of the salt, just the physical form. Hope this helps! :)

6 0

2 years ago

Read 2 more answers

How did rutherford know that the nucleus was positively charged?

AleksAgata [21]

'cause alphe-particle which was +ve charge, get repulsion from the atom, so he deducted that.......

3 0

2 years ago

Help please. Which mass of urea, CO(NH2)2, contains the same mass of nitrogen as 101.1 g of potassium nitrate?

Masja [62]

Did u mean mass of potassium nitrate or the mass of nitrogen in potassium nitrate

6 0

3 years ago

A 25.0 g sample of an alloy was heated to 100.0 oC and dropped into a beaker containing 90 grams of water at 25.32 oC. The tempe

kaheart [24]

Answer:

The specific heat of the alloy $C_{a} = 0.37 \frac{KJ}{Kg K}$

Explanation:

Mass of an alloy $m_{a}$ = 25 gm

Initial temperature $T_{a}$ = 100°c = 373 K

Mass of water $m_{w}$ = 90 gm

Initial temperature of water $T_{w}$ = 25.32 °c = 298.32 K

Final temperature $T_{f}$ = 27.18 °c = 300.18 K

From energy balance equation

Heat lost by alloy = Heat gain by water

$m_{a}$ $C_{a}$ [ $T_{a}$ - $T_{f}$ ] = $m_{w}$ $C_w$ ( $T_{f}$ - $T_{w}$ )

25 × $C_{a}$ × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)

$C_{a} = 0.37 \frac{KJ}{Kg K}$

This is the specific heat of the alloy.

6 0

2 years ago

What is the charge on a hypothetical ion with 85 protons and 83 electrons?

lys-0071 [83]

Explanation:

hope this answer was helpful

7 0

2 years ago