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ale4655 [162]
3 years ago
14

How is the law of conservation of matter represented in a chemical reaction?

Chemistry
1 answer:
blondinia [14]3 years ago
5 0

Answer:

By balancing the chemical equation  

Explanation:

The Law of Conservation of Matter states that matter cannot be destroyed nor created.

That is, you must have the same amount of matter before and after a reaction.

Atoms are made of matter, so you must have the same number of each type of atom in the reactants as in the products. You must balance the equation.

Consider the reaction

2H₂ + O₂ ⟶ 2H₂O

You must have 2s in front of H₂ and H₂O to balance the atoms.

They give you four atoms of H and two atoms of O on each side of the arrow.

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At constant pressure, how are the temperature and volume of a gas related?
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Answer:

The volume of a given gas sample is directly proportional to its absolute temperature at constant pressure (Charles's law). The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law).

4 0
2 years ago
What determines density?
LUCKY_DIMON [66]

Answer:

D = m/v.

Explanation:

The density of a substance is the relationship between the mass of the substance and how much space it takes up (volume). The mass of atoms, their size, and how they are arranged determine the density of a substance. Density equals the mass of the substance divided by its volume;

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3 years ago
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Predict the products for the following chemical reaction: H2 + O2 →
RSB [31]
The answer is C I got it right so hope it helped ;)
6 0
3 years ago
A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati
prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

k=\frac{2.303}{48.0}\log\frac{53500}{42520}

k=9.98\times 10^{-2}hr^{-1}

Now we have to calculate the half-life.

k=\frac{0.693}{t_{1/2}}

9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}

t_{1/2}=6.94hr

Therefore, the half life of 28-Mg in hours is, 6.94

8 0
3 years ago
An ionic bond is best described as
LekaFEV [45]
The answer would be B the transfer of electrons from one atom to another
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3 years ago
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