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serg [7]
3 years ago
5

Which is a group pragram acoholics recover in

Physics
1 answer:
Svetradugi [14.3K]3 years ago
4 0
A group program alcoholics recover in is A-A
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Satellites can focus on specific latitudes using:
Fittoniya [83]
B- east west orbits
4 0
3 years ago
You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between
9966 [12]

Answer:

(a) 0.061 m/s

(b) 0.103 m/s

Explanation:

From the law of conservation of momentum, the sum of initial momentum equals the sum of final momentum

Momentum, p=mv where m is the mass and v is the velocity

m_1v_1=(m_1+m_2)v_c where v_c is the common velocity, v_1 is the velocity of the ball m_1 and m_2 are masses of the ball and person respectively

Substituting the given values then

0.400\times 11.5 = (0.400+75)v_c\\v_c=0.061007958\approx 0.061 m/s

(b)

Momentum, p=mv where m is the mass and v is the velocity

m_1v_1=m_1v_2+m_2v_3

v_1 is the velocity of the ball , v_2 is the velocity of ball afterwards and v_3 is your speed, m_1 and m_2 are masses of the ball and person respectively. Since it bounces back, we give it a negative value hence

0.400\times 11.5= 0.4\times -7.8+75v_3\\v_3=0.102933333\approx 0.103 m/s

3 0
3 years ago
How much time would it take for the sound of thunder to travel 2000 meters if sound travels of 330 meters per sec
Lubov Fominskaja [6]
2000÷330=6.06 repatant so the answer would be about 6.06 seconds
4 0
4 years ago
Read 2 more answers
If, instead, the ball is revolved so that its speed is 3.7 m/s, what angle does the cord make with the vertical?
Delicious77 [7]

Complete Question:

A 0.50-kg ball that is tied to the end of a 1.5-m light cord is revolved in a horizontal plane, with the cord making a 30° angle with the vertical.

(a) Determine the ball’s speed. (b) If, instead, the ball is revolved so that its

speed is 3.7 m/s, what angle does the cord make with the vertical?

(Check attached image for the diagram.)

Answer:

(a) The ball’s speed, v = 2.06 m/s

(b) The angle the cord makes with the vertical is 50.40⁰

Explanation:

If the ball is revolved in a horizontal plane, it will form a circular trajectory,

the radius of the circle, R = Lsinθ

where;

L is length of the string

The force acting on the ball is given as;

F = mgtanθ

This above is also equal to centripetal force;

mgTan \theta = \frac{mv^2}{R} \\\\Recall, R = Lsin \theta\\\\mgTan \theta = \frac{mv^2}{Lsin \theta}\\\\v^2 = glTan \theta sin \theta\\\\v = \sqrt{glTan \theta sin \theta} \\\\v = \sqrt{(9.8)(1.5)(Tan30)(sin30)} \\\\v = 2.06 \ m/s

(b) when the speed is 3.7 m/s

v = \sqrt{glTan \theta sin \theta} \ \ \ ;square \ both \ sides\\\\v^2 = glTan \theta sin \theta\\\\v^2 = gl(\frac{sin \theta}{cos \theta})   sin \theta\\\\v^2 = \frac{gl*sin^2 \theta}{cos \theta} \\\\v^2 =  \frac{gl*(1- cos^2 \theta)}{cos \theta}\\\\gl*(1- cos^2 \theta) = v^2cos \theta\\\\(9.8*1.5)(1- cos^2 \theta) = (3.7^2)cos \theta\\\\14.7 - 14.7cos^2 \theta = 13.69cos \theta\\\\14.7cos^2 \theta  + 13.69cos \theta - 14.7 = 0 \ \ \ ; this \ is \ quadratic \ equation\\\\

Cos\theta = \frac{13.69\sqrt{13.69^2 -(-4*14.7*14.7)} }{14.7} \\\\Cos \theta = 0.6374\\\\\theta = Cos^{-1}(0.6374)\\\\\theta = 50.40 ^o

Therefore, the angle the cord makes with the vertical is 50.40⁰

7 0
3 years ago
A 20kg rock is sliding on a rough, horizontal surface at 8 m/s and eventually stops due to friction. the coefficient of kinetic
Dmitry_Shevchenko [17]

Answer:

156watts

Explanation:

M = 20

U = 0.200

Vo = 8.0

We are to get p

P = w/t

W = 1/2(vf²-Vo²)

The final velocity is 0

W =-1/2*20*8²

= -640J

Acceleration = -ug

= -0.200*9.8

= -1.96m/s^-2

We are to get t

t = 8/1.96

= 4.1s

P = w/t

= 640/4.1

= 156 watts

156watts is the average power that is produced by friction as the rock stops.

6 0
3 years ago
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