Question

How many moles are in 1.29x10^24 hydrogen atoms in HF

Answer 1

We know that, 1 mole of any substance contain 6.022 X 10^23 atoms/molecules.

Thus,  6.022 X 10^23 atoms = 1 mole
Therefore, 1.29x10^24 = $\frac{1.29X10^2^4}{6.022X10^2^3}$
                                     = 2.14

Thus, 2.14 moles are present in 1.29x10^24 hydrogen atoms in HF.

Answer 2

Explanation:

According to Avogadro's number there are $6.023 \times 10^{23}$ atoms present in one mole.

Therefore, we will calculate the number of moles present in $1.29 \times 10^{24}$ atoms as follows.

                 Number of moles = $\frac{1.29 \times 10^{24}atoms}{6.023 \times 10^{23}}atoms/mol$

                                             = 2.14 mol

Therefore, we can conclude that there are 2.14 moles present in $1.29 \times 10^{24}$ hydrogen atoms in HF.