-1 - -1.
-1 + 1.
0.
The answer is 0.
Answer:
Step-by-step explanation:
a+b+c=0, a+b=-c,a+c=-b, b+c=-a
(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=
a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=
a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=
a^3+b^3+c^3+3a^2*(-a)+3c^2*(-c)+3b^2*(-b)+6abc=
a^3+b^3+c^3-3a^3-3c^3-3b^3+6abc=
6abc-2a^3-2b^3-2c^3=2(3abc-a^3-b^3-c^3)=
2*[3abc-(a^3+b^3+c^3)]=0
so 3abc-(a^3+b^3+c^3)=0
so a^3+b^3+c^3=3abc
Answer:
2.7
Step-by-step explanation:
x^2=5.8*1.3=7.54
x=V7.54=2.7
The correct interval notation for the continuous set of all numbers between 5 and 6, including 5, but not including 6 is [5, 6) option (C) is correct.
<h3>What is interval notation?</h3>
It is defined as the representation of a set of values that satisfy a relation or a function. It can be represented as open brackets and close bracket the close the brackets means the value is at the close bracket also included, and open bracket means the value at the open bracket does not include.
We have:
Continuous set of all numbers between 5 and 6, including 5, but not including 6.
From the above statement we can represent the number in the interval notation:
The numbers are between 5 and 6.
(5, 6)
As it is mentioned that 5 is included and 6 is not included, then:
[5, 6)
Thus, the correct interval notation for the continuous set of all numbers between 5 and 6, including 5, but not including 6 is [5, 6) option (C) is correct.
Learn more about the interval notation here:
brainly.com/question/13048073
#SPJ1
Answer:
= 17.7 ( rounded off to one decimal place)
STAY SAFE, GOD BLESS YOU :)
Step-by-step explanation:
851 ÷ 48
= 17.7291
= 17.7 ( rounded off to one decimal place)
