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3 years ago

Can anyone help me out with this question please? It has to be right thanks so much

Physics

1 answer:

Vladimir79 [104]3 years ago

8 0

it is basalt which is an igneous rock

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What material of mass 39g,has a volume of 5cm^3

insens350 [35]

The material of density 7.8 g/cm³

4 0

3 years ago

A piece of wood has mass of 250g and volume of 400cm cubed. what is its density

Zigmanuir [339]

Answer:

$0.625 \: g {cm}^{ - 3}$

Explanation:

$density \: = \frac{mass}{volume} \\ \\ = \frac{250}{400} \\ \\ = 0.625 \: g {cm}^{ - 3}$

5 0

2 years ago

If the force on the tympanic membrane (eardrum) increases by about 1.4 N above the force from the atmospheric pressure, the memb

Sveta_85 [38]

Answer:

10.58 ft

Explanation:

Force, F = 1.4 N

Diameter of membrane = 7.4 mm

radius of membrane, r = 7.4 / 2 = 3.7 mm = 3.7 x 10^-3 m

Area, A = 3.14 x (3.7 x 10^-3)^2 = 4.3 x 10^-5 m^2

Density, d = 1.03 x 10^3 kg/m^3

Pressure at depth, P = h x d x g

Let h be the depth.

Pressure = force / Area

h x 1.03 x 10^3 x 9.8 = 1.4 / (4.3 x 10^-5)

h = 3.225 m = 10.58 ft

Thus, the depth of water is 10.58 ft.

6 0

3 years ago

A potter's wheel has the shape of a solid uniform disk of mass 7 kg and radius 0.65 m. It spins about an axis perpendicular to t

ozzi

Answer:

1.832 kgm^2

Explanation:

mass of potter's wheel, M = 7 kg

radius of wheel, R = 0.65 m

mass of clay, m = 2.1 kg

distance of clay from centre, r = 0.41 m

Moment of inertia = Moment of inertia of disc + moment f inertia of the clay

I = 1/2 MR^2 + mr^2

I = 0.5 x 7 x 0.65 x 0.65 + 2.1 x 0.41 x 0.41

I = 1.47875 + 0.353

I = 1.832 kgm^2

Thus, the moment of inertia is 1.832 kgm^2.

5 0

3 years ago

A boat heads north in still water at 4.5 m/s directly across a river that is running east at 3.0 m/s. What is the velocity of th

Fynjy0 [20]

<h2>Velocity of the boat with respect to Earth is 5 m/s 56.31° north of east</h2>

Explanation:

A boat heads north in still water at 4.5 m/s directly across a river that is running east at 3.0 m/s.

Let north be positive y axis and east be positive x axis.

We have

Velocity of boat = 4.5 j m/s

Velocity of river = 3 i m/s

Velocity of the boat with respect to Earth = 3 i + 4.5 j

$\texttt{Magnitude of velocity = }\sqrt{3^2+4.5^2}\\\\\texttt{Magnitude of velocity = }5.41m/s$

$\texttt{Angle = }tan^{-1}\left ( \frac{4.5}{3}\right )\\\\\texttt{Angle = }56.31^0$

That is 56.31° north of east.

Velocity of the boat with respect to Earth is 5 m/s 56.31° north of east

4 0

3 years ago

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