4. What is the formula for potassium dichromateo?b

A spherical aluminum ball of mass 1.26 kg contains an empty spherical cavity that is concentric with the ball. The ball barely f

V125BC [204]

The outer radius of the ball = 6.70cm.

<h3>What is Buoyant Force?</h3>

The upward force applied to an object that is fully or partially submerged in a fluid is known as the buoyant force.

Given: Mass of aluminum ball = $m_{b}=1.26kg$

To find: The outer radius of the ball.

Finding:

As Buoyant Force = $F_{b}=e\times(g)\times\frac{4}{3}\pi(r)^{3}$ ,

The weight of the ball should be equal to the buoyant force since it floats on the water.

That is,

=> $1.26=e_{water}(g)(\frac{4}{3}\pi(r_{outer})^{3})$

=> $r_{outer}=(\frac{3\times1.26}{g\times(e_{water})4\times3.14})^\frac{1}{3}$

Upon substitution of values of $e_{water}$ and g, we get: $r_{outer}=6.70cm$

Hence, the outer radius of the ball = 6.70cm

To learn more about Buoyant Force, refer to the link: brainly.com/question/17009786

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4 0

2 years ago

Light of wavelength 656 nm and 410 nm emitted from a hot gas of hydrogen atoms strikes a grating with 5300 lines per centimeter.

padilas [110]

Answer:

$20.32^{\circ}$ and $44.08^{\circ}$

$12.56^{\circ}$ and $25.77^{\circ}$

Explanation:

$\lambda$ = Wavelength

$\theta$ = Angle

m = Order

Distance between grating is given by

$d=\dfrac{1}{5300}\\\Rightarrow d=0.0001886\ \text{cm}$

$\lambda=656\ \text{nm}$

We have the relation

$d\sin\theta=m\lambda\\\Rightarrow \theta=\sin^{-1}\dfrac{m\lambda}{d}$

m = 1

$\theta=\sin^{-1}\dfrac{1\times 656\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=20.35^{\circ}$

m = 2

$\theta=\sin^{-1}\dfrac{2\times 656\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=44.08^{\circ}$

The first and second order angular deflection is $20.32^{\circ}$ and $44.08^{\circ}$

$\lambda=410\ \text{nm}$

m = 1

$\theta=\sin^{-1}\dfrac{1\times 410\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=12.56^{\circ}$

m = 2

$\theta=\sin^{-1}\dfrac{2\times 410\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=25.77^{\circ}$

The first and second order angular deflection is $12.56^{\circ}$ and $25.77^{\circ}$ .

4 0

3 years ago

Hydroelectric power uses: wind water coal the sun

Ivanshal [37]

hydroelectric uses water

3 0

3 years ago

The ________ method is duct sizing that considers the each duct section has the same air velocity.

Gennadij [26K]

The equal velocity approach for duct size assumes that the air velocity in each duct segment is the same.

How fast is the air moving through a duct?

The most common unit of air velocity (distance traveled in a unit of time) is feet per minute (FPM). The amount of air passing past a location in the duct per period of time may be calculated by multiplying the airflow by the area of the duct. The standard unit for volume flow is cubic feet per minute (CFM).

What happens when the size of ducts changes to the airflow?

Result for an image The equal velocity technique for duct size makes the assumption that air velocity is constant across the entire duct system.

The main lesson to be learned from this is that when air goes from a bigger to a narrower duct, its velocity rises. The velocity drops when it transitions from a shorter to a bigger duct. The flow rate or the amount of air passing through the duct in cubic feet per minute is the same in all scenarios.

Learn more about air velocity here:

brainly.com/question/3255148

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5 0

2 years ago

A brick has a length of 15 cm width of 10 cm and height of 5 cm. What is the volume if the brick

Pie

Answer:

750cm³

Explanation:

volume = length × width × height

15 × 10 × 5 = 750

750cm³

3 0

3 years ago

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