3 years ago

Match each context to the type of the law that is most suitable for it.

Engineering

1 answer:

Bas_tet [7]3 years ago

5 0

Answer:

sorry i dont understand the answer

Explanation:

but i think its a xd jk psml lol

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An aircraft is flying at 300 mph true airspeed has a 50 mph tailwind. What is its ground speed?

Free_Kalibri [48]

Answer:

304.13 mph

Explanation:

Data provided in the question :

The Speed of the flying aircraft = 300 mph

Tailwind of the true airspeed = 50 mph

Now,

The ground speed will be calculated as:

ground speed = $\sqrt{300^2+50^2}$

The ground speed = $\sqrt{92500}$

The ground speed = 304.13 mph

Hence, the ground speed is 304.13 mph

8 0

3 years ago

Shear _______ can be directly computed from the angle of twist and the specimen dimensions. (a)- Stress (b)- Modulus (c)- Strain

fgiga [73]

Answer:

c) Strain

Explanation:

For example, the shear strain “γ” on the surface of the rod is determined by measuring the relative angle of twist “φg” over a gage length “Lg”.

6 0

3 years ago

tresset_1 [31]

Answer:

A because i know thats it

8 0

3 years ago

consider a packed bed of 10cm diameter concrte (stone mix) spheres to be used as a thermal (energy) storage sysytem initailly th

hodyreva [135]

Answer: ok bit sp are 16 degrees

Explanation:

8 0

2 years ago

Tool life testing on a lathe under dry cutting conditions gauge 'n' and 'C' of Taylor tool life equation as 0.12 and 130 m/min.

Tom [10]

Answer:

So % increment in tool life is equal to 4640 %.

Explanation:

Initially n=0.12 ,V=130 m/min

Finally C increased by 10% , V=90 m/min

Let's take the tool life initial condition is $T_1$ and when C is increased it become $T_2$ .

As we know that tool life equation for tool

$VT^n=C$

At initial condition $130\times (T_1)^{0.12}=C$ ------(1)

At final condition $90\times (T_2)^{0.12}=1.1C$ -----(2)

From above equation

$\dfrac{130\times (T_1)^{0.12}}{90\times (T_2)^{0.12}}=\dfrac{1}{1.1}$

$T_2=47.4T_1$

So increment in tool life = $\dfrac{T_2-T_1}{T_1}$

= $\dfrac{47.4T_1-T_1}{T_1}$

So % increment in tool life is equal to 4640 %.

7 0

2 years ago