Answer:
specific volume = 1.025 m³/kg
Explanation:
given data
total mass m1 +m2 = 80 kg
specific volume = 0.8 m³/kg
occupies volume v1 = 40 m³
other gas specific volume = 1.4 m³
to find out
How much volume is occupied by the second gas and what is the specific volume of the mixture
solution
we know that density is reciprocal of specific volume and here gas is not interacting
so total specific volume is assume so ratio is total volume to total mass
and
specific volume = 
here ρ is density
so ρ1 = 
= 1.25 kg/m³
and ρ2 = 
= 0.714 kg/m³
and
so m1 = ρ1v1 = 1.25 × 40 = 50 kg
and m2 = 80 - 50 = 30 kg
so
v2 = 
v2 = 
= 42 m³
so volume occupied by second das = 42 m³
and
specific volume of mixture will be
specific volume of mixture = 
specific volume = 
specific volume = 1.025 m³/kg
The maximum volume flow rate of kerosene is 8.3 L/s
<h3>What is the maximum volume flow rate?</h3>
In fluid dynamics, the maximum volume flow rate (Q) is the volume or amount of fluid flowing via a required cross-sectional area per unit time.
In fluid mechanics, using the following relation, we can determine the maximum volume flow rate of kerosene.
- Power = mass flow rate(m) × specific work(w) --- (1)
- Specific work = acceleration due to gravity (g) × head (h) ---- (2)
- Mass flow rate (m) = density (ρ) × volume flow rate (Q) --- (3)
By combining the three equations together, we have:
The power gained through the fluid pump to be:
Making Q the subject, we have:
where:
- P = 2 kW = 2000 W
- ρ = 0.820 kg/L
- g = 9.8 m/s
- h = 30 m
Q = 0.008296 m³/s
Q ≅ 8.3 L/s
Learn more about the maximum volume flow rate here:
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