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Rudik [331]
3 years ago
12

In Linnean taxonomy, the most unique level is _____.

Chemistry
1 answer:
vekshin13 years ago
6 0

Answer:

the most unique level is Species

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The chemical equation shows iron(III) phosphate reacting with sodium sulfate. 2FePO4 + 3Na2SO4 Fe2(SO4)3 + 2Na3PO4 What is the t
slava [35]

<u>Answer:</u> The theoretical yield of iron(III) sulfate is 26.6 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of iron(III) phosphate = 20.00 g

Molar mass of iron(III) phosphate = 150.82 g/mol

Putting values in equation 1, we get:

\text{Moles of iron(III) phosphate}=\frac{20g}{150.82g/mol}=0.133mol

The given chemical equation follows:

2FePO_4+3Na_2SO_4\rightarrow Fe_2(SO_4)_3+2Na_3PO_4

As, sodium sulfate is present in excess. So, it is considered as an excess reagent.

Thus, iron(III) phosphate is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of iron(III) phosphate produces 1 mole of iron(III) sulfate

So, 0.133 moles of iron(III) phosphate will produce = \frac{1}{2}\times 0.133=0.0665moles of iron(III) sulfate

Now, calculating the mass of iron(III) sulfate from equation 1, we get:

Molar mass of iron(III) sulfate = 399.9 g/mol

Moles of iron(III) sulfate = 0.0665 moles

Putting values in equation 1, we get:

0.0665mol=\frac{\text{Mass of iron(III) sulfate}}{399.9g/mol}\\\\\text{Mass of iron(III) sulfate}=(0.0665mol\times 399.9g/mol)=26.6g

Hence, the theoretical yield of iron(III) sulfate is 26.6 grams

8 0
4 years ago
Using the Lewis dot structures of magnesium and oxygen, predict the ionic formula
Blizzard [7]

Answer:

(edit: nvm I figured it out, here is the answer)

Explanation:

7 0
3 years ago
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I can’t read ? This what does it say
7 0
3 years ago
What is a control group used for?
jeka94
  • The control group defined as  a group that does not include any change to the inconstant being tested. Why is a control crucial in an experiment? The control group is crucial because it acts as a benchmark to variatethe results of the experiment to. The experimental group is the group that the scientist is examing . The experimental group receives a change to a variable, or the conditions allowed to change in the experiment.
  • There are two types of control group :   Positive control groups and Negative control groups
  • The positive control group is a group that is contrive to produce the effect you are looking for in the experimental group. The positive control group shows the scientists that the craved results are achievable . This helps stop false negative outcome in the experimental group, where a negative result is receive but is due to a failure in the experiment instead than a truly negative result based on the experimental conditions.
  • A negative control group is a group that is not exposed to the different  scientist is testing, called the independent variable. A negative control group function as a benchmark to secure that the results that are got are actually due to the independent variable and not anything else

To know more about control group visit :

brainly.com/question/14308149

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3 0
1 year ago
⚠️HELP⚠️
morpeh [17]

Answer:

The balanced equation is :

Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2(g)

7 0
3 years ago
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