The question is not complete and the first part missing is;
A particular uranium alloy has a density of 18.75 g/cm³. Please answer the following questions below, providing the explanation to your answers.
a. What volume is occupied by a critical mass of 49 kg of this alloy?
Answer:
A) 2610 cm³
B) Mbase < Ma < Mv < Mbask
Explanation:
a) density of uranium alloy = 18.75 g/cm³ = 18750 kg/m³
Mass (m) = 16kg
We know that;
volume = mass / density
Thus, volume = 49kg / 18750kg/m³ = 2.61 x 10^(-3) m³ = 2610 cm³
b) Mass is now reduced to 16kg instead of 49kg. Thus,
Volume = 16/18750 = 0.000853 m³ or 853 cm³
From research, the diameters of baseball, volleyball and basketball are;
Baseball = 7.5 cm
Volleyball = 21.3 cm
Basketball = 24.26cm
baseball:
Since diameter is about 7.5 cm
then V = πd³/6 = π(7.5³)/6 = 220.89 cm³
volleyball: diameter is around 21.3 cm³, then V =π(21.3³)/6 = 5059.86 cm³
basketball: diameter around 24.26, then V =π(25³)/6 = 8181.23 cm³
Lets call the Volume of Alloy Ma while Mass of Baseball is Mbase
Mass of volleyball is Mv while mass of basketball is Mbask.
So comparing the volumes, we have;
Mbase < Ma < Mv < Mbask