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Tanzania [10]
4 years ago
6

ABCD / EFG = HIBCE solve for D. What is the answer

Physics
1 answer:
vredina [299]4 years ago
7 0

Answer:

d=\frac{e^{2}*f*g*h*i }{a}

Explanation:

Multiply right stide by "EFG", left side will be only ABCD. Then devide right side by "ABC", leaving left side as  just D. Cancel out numbers both in numerator and denominator of right

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What is the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b?
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The energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.

<h3>Change in energy level of the electron</h3>

When photons jump from a higher energy level to a lower level, they emit or radiate energy.

The change in energy level of the electrons is calculated as follows;

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Learn more about energy level here: brainly.com/question/14287666

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