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3 years ago

Can some please help me with this. Will brainliest

Physics

1 answer:

barxatty [35]3 years ago

8 0

Answer:

1)chest

2)deltoid

3)bicep

4)abs

5)quadriceps

6)lats

7)triceps

8)glutes

9)calves

10)hamstring

11)trapezuis

Explanation:

the explanation is the picture

good luck :)

hopefully, this helps

have a nice day !!

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Where:

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$\theta)$ the angle between incident phhoton and the scatered photon.

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$\Delta \lambda_{max}=2\lambda_{c}$ (3)

Now, let's find the angle that will produce a fourth of this maximum value found in (3):

$\frac{1}{4}\Delta \lambda_{max}=\frac{1}{4}2\lambda_{c}(1-cos\theta)$ (4)

$\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}(1-cos\theta)$ (5)

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$0=cos\theta$

$\theta=cos^{-1} (0)$

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