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3 years ago

Can some please help me with this. Will brainliest

Physics

1 answer:

barxatty [35]3 years ago

8 0

Answer:

1)chest

2)deltoid

3)bicep

4)abs

5)quadriceps

6)lats

7)triceps

8)glutes

9)calves

10)hamstring

11)trapezuis

Explanation:

the explanation is the picture

good luck :)

hopefully, this helps

have a nice day !!

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A bullet of mass M1 is fired towards a block of mass m2 initially at rest at the edge of a frictionless table of height h as in

pantera1 [17]

The ratio of time of flight for inelastic collision to elastic collision is 1:2

The given parameters;

mass of the bullet, = m₁
mass of the block, = m₂
initial velocity of the bullet, = u₁
initial velocity of the block, = u₂

Considering inelastic collision, the final velocity of the system is calculated as;

$m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\$

The time of motion of the system form top of the table is calculated as;

$v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)$

Considering elastic collision, the final velocity of the system is calculated as;

$m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2$

Apply one-directional velocity

$u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1$

Substitute the value of $v_1$ into the above equation;

$m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)$

where;

$v_2$ is the final velocity of the block after collision

Since the bullet bounces off, we assume that only the block fell to the ground from the table.

The time of motion of the block is calculated as follows;

$v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)$

The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;

$\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2$

Learn more about elastic and inelastic collision here: brainly.com/question/7694106

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2 years ago

Optimists usually have a higher degree of wellness than pessimists. O True False

photoshop1234 [79]

Answer:

True

Explanation:

Studies regularly show that optimists are more likely to maintain better physical health than pessimists, including a 50% lower risk of cardiovascular disease and greater survival rates when fighting cancer.

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3 years ago

An electric hoist does 56,447 J of work in raising 115 kg load. How high (in meters) was the load lifted?

Ugo [173]

$\\ \rm\rightarrowtail W=mgh$