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3 years ago

Can some please help me with this. Will brainliest

Physics

1 answer:

barxatty [35]3 years ago

8 0

Answer:

1)chest

2)deltoid

3)bicep

4)abs

5)quadriceps

6)lats

7)triceps

8)glutes

9)calves

10)hamstring

11)trapezuis

Explanation:

the explanation is the picture

good luck :)

hopefully, this helps

have a nice day !!

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A paintball is shot horizontally in the positive x direction at time t after the ball is shot it is 4 cm to the right and 4 cm b

Artist 52 [7]

<u>Answer:</u>

At time 2t the paint ball is at 8 cm to the right and 16 cm to the bottom

<u>Explanation:</u>

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Considering the horizontal motion of paint ball

Distance traveled during time t = 4 cm

Initial velocity = u m/s

Acceleration = 0 $m/s^2$

So $4 = u*t+\frac{1}{2} *0*t^2\\ \\ u = \frac{4}{t}$

Now at time 2t,

$S= u*2t+\frac{1}{2} *0*(2t)^2\\ \\=\frac{4}{t} *2t\\ \\ =8cm$

So horizontal distance traveled in time 2t = 8 cm to the right

Now considering the vertical motion of paint ball

Distance traveled during time t = 4 cm

Initial velocity = 0 m/s

Acceleration = -g $m/s^2$

$4=0*t-\frac{1}{2} *g*t^2\\ \\ t^2=\frac{-8}{g}$

At time 2t,

$S=0*2t-\frac{1}{2} *g*(2t)^2\\ \\ =-\frac{1}{2} *g*4*\frac{-8}{g}\\ \\ =16 cm$

So vertical distance traveled in time 2t = 16 cm to the bottom

6 0

3 years ago

what frequency of light must an electron in hydrogen absorb to jump from the n=2 state to the n=5 state? (a) 2.86 Hz (b) 4.08 Hz

Ostrovityanka [42]

Answer:

Explanation:

Find the level energy of n=2 and n=5, using the formula:

$E = -E_0/n^2$

where $E_0=13.6eV$

$E_2 =\frac{-13.6}{2^2}=-3.4eV$

$E_5 =\frac{-13.6}{5^2}=-0.544eV$

To jump from n=2 to n=5 the electron absorbs a photon with energy equal to $(-0.544) - (-3.4)=2.856eV$ , using the next formula to find specific wavelength $\lambda$ to that energy

$E = hc/\lambda$

Where $c$ is the speed of light ( $c=3 \times10^8m/s$ ) and $h$ is Planck's constant ( $h=4.14\times10^{-15}eVs$ ). Solve for $\lambda$ :

$E = hc/\lambda\\\lambda E = hc\\\lambda = \frac{hc}{E} \\\lambda = \frac{(4.14\times10^{-15})(3 \times10^8)}{2.856}=4.35\times10^{-7}m$

The frequency of this wavelength is calculated with this formula:

$f=\frac{c}{\lambda}$

$f=\frac{3\times10^8}{4.3487\times10^{-7}} =6.89\times10^{14}Hz\approx6.9\times10^{14}Hz$

8 0

4 years ago

An object that sinks in water has a mass in air of 0.0675 kg. Its apparent mass when submerged in water is 0.0424 kg. What is th

Tasya [4]

Answer:

1. SG

true

=2.689

2. The object is probably some sort of minerals and rocks such as Feldspar, Corals, Beryl, etc.

Explanation:

Given:

mass in the air= 0.0675 kg

mass in water= 0.0424 kg

6 0

3 years ago

A 2-kg ball is moving with a speed of 4 m/s, and a 4-kg ball is moving with a speed of 2 m/s. What can you conclude about the of

Mila [183]

<h2>Kinetic energy of mass 4 kg ball is less than kinetic energy of mass 2 kg ball</h2>

Explanation:

Kinetic energy = 0.5 x Mass x Velocity²

For ball of mass 2 kg

Mass, m = 2 kg

Velocity, v = 4 m/s

Kinetic energy = 0.5 x 2 x 4² = 16 J

For ball of mass 4 kg

Mass, m = 4 kg

Velocity, v = 2 m/s

Kinetic energy = 0.5 x 4 x 2² = 8 J

Kinetic energy of mass 4 kg ball is less than kinetic energy of mass 2 kg ball

4 0

4 years ago

A backyard swimming pool with a circular base of diameter 6.00m is filled to depth 1.50m. (b) Two persons with combined mass 150

Mashutka [201]

The pressure increase at the bottom of the pool after they enter the pool and float is 106.103 Pa.

<h3>What is absolute pressure?</h3>

Absolute pressure is the force that exists in a space when there is no matter present, or when there is a perfect vacuum. This absolute zero serves as the baseline for measurements in absolute pressure. The measurement of barometric pressure is the greatest illustration of an absolute referenced pressure. In order to determine absolute pressure, a complete vacuum is used. In contrast, gauge pressure is the amount of pressure that is measured in relation to atmospheric pressure, also referred to as barometric pressure.

given,

diameter = 6 m

depth = h = 1.5 m

Atmospheric pressure = P₀ = 10⁵ Pa

a) absolute pressure

P = P₀ + ρ g h

P = 10⁵ + 1000 x 10 x 1.5

P = 1.15 x 10⁵ Pa

b) When two person enters into the pool,

mass of the two person = 150 Kg

weight of water level displaced exists equal to the weight of person.

$\rho \mathrm{Vg}=2 \mathrm{mg} \\$