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BartSMP [9]
3 years ago
12

Calculate how much calories you have if you have 8 joule ? please:

Physics
1 answer:
goblinko [34]3 years ago
5 0

Answer:

If you have 8 Joules of energy that means you have 1.912 calories.

Explanation:

As we know that one calorie is equal to 4.184 J. We need to calculate in 8 Joules of energy how many calories are present.

We know that,

For 1 calorie = 4.184 J

For ? = 8 Joules

To obtain calories in 8 Joules. Divide 8 by 4.184.

\text { Calorie }=\frac{\text { Joule }}{4.184}

\text { calorie }=\frac{8}{4.184}

calorie=1.912

Therefore, 8 J = 1.912 calorie.

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Fynjy0 [20]

combustion of fossil fuels would be the correct answer when dealing with the alteration of the carbon cycle.

3 0
4 years ago
Consider the potential energy diagram shown below. This graph shows the chemical potential energy in a reaction system over time
kolbaska11 [484]

Answer:

A. Endothermic reaction.

B. +150KJ.

C. 250KJ.

Explanation:

A. The graph represents endothermic reaction because the heat of the product is higher than the heat of the reactant.

B. Determination of the enthalpy change, ΔH for the reaction. This can be obtained as follow:

Heat of reactant (Hr) = 50KJ

Heat of product (Hp) = 200KJ

Enthalphy change (ΔH) =..?

Enthalphy change = Heat of product – Heat of reactant.

ΔH = Hp – Hr

ΔH = 200 – 50

ΔH = +150KJ

Therefore, the enthalphy change for the reaction is +150KJ

C. The activation energy for the reaction is the energy at the peak of the diagram.

From the diagram, the activation energy is 250KJ.

6 0
3 years ago
What is the magnitude of the force acting on a spring with a spring constant of 275 N/m that is stretched 14.3 cm?
Travka [436]
15 i thank 
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8 0
3 years ago
Which statement is the contrapositive of:
HACTEHA [7]

Answer:

E.two angles are vertical angles if, and only if they are not adjacent angles

5 0
3 years ago
Compare the time period of two simple pendulums of length 4m and 16m at a place.
Vlad1618 [11]

Answer:

the period of the 16 m pendulum is twice the period of the 4 m pendulum

Explanation:

Recall that the period (T) of a pendulum of length (L)  is defined as:

T=2\,\pi\,\sqrt{ \frac{L}{g} }

where "g" is the local acceleration of gravity.

SInce both pendulums are at the same place, "g" is the same for both, and when we compare the two periods, we get:

T_1=2\,\pi\,\sqrt{\frac{4}{g} } \\T_2=2\,\pi\,\sqrt{\frac{16}{g} } \\ \\\frac{T_2}{T_1} =\sqrt{\frac{16}{4} } =2

therefore the period of the 16 m pendulum is twice the period of the 4 m pendulum.

5 0
3 years ago
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