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Tanya [424]
3 years ago
10

Which phrases describe space observatories?

Chemistry
1 answer:
amid [387]3 years ago
7 0

Answer:1 and 3

Explanation: got it right

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A balloon contains 3.20 L of helium. The pressure is reduced to 59.0 kPa, and the
pshichka [43]

Answer:

101.4pKa

Explanation:

Given parameters:

Initial Volume of helium  = 3.20L

Final pressure of helium  = 59kPa

Final volume on helium gas = 5.5L

Unknown:

Initial pressure exerted on the balloon = ?

Solution;

To solve this pressure - volume problem, we simply apply the Boyle's law.

It states that "the volume of a fixed mass gas varies inversely as the pressure changes if the temperature is constant".

  Mathematically;

         P1 V1  = P2 V2

Now, insert parameters and solve;

         P1 x 3.2 = 59 x 5.5

          P1  = 101.4pKa

4 0
3 years ago
F(x) = x^2 +1<br> What is f(f(x))?
san4es73 [151]

Answer:

(f(x))

f(x) + 3

[3f(x)

Explanation:

5 0
3 years ago
2. Which is not true of an electric current?
daser333 [38]
B. Electric current requires a specific path to follow.
4 0
2 years ago
Which of the following is NOT a chemical reaction?
Damm [24]
Ice melting from water. Nothing has changed except the state of matter.
6 0
3 years ago
Consider the reaction below. If you start with 4.00 moles of C3H8 (propane) and 4.00 moles of O2 , how many moles of propane wou
fgiga [73]

Answer:

0.800 mol

Explanation:

We have the amounts of two reactants, so this is a limiting reactant problem.  

We know that we will need a balanced equation with moles of the compounds involved.  

Step 1. <em>Gather all the information</em> in one place.

            C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O

n/mol:  4.00    4.00

===============

Step 2. Identify the <em>limiting reactant </em>

Calculate the <em>moles of CO₂</em> we can obtain from each reactant.  

<em>From C₃H₈:</em>

The molar ratio of CO₂: C₃H₈ is 3:1

Moles of CO₂ = 4.00 × 3/1

Moles of CO₂ = 12.0 mol CO₂

<em>From O₂</em>:

The molar ratio of CO₂: O₂ is 3:5.

Moles of CO₂ = 4.00 × ⅗

Moles of CO₂ = 2.40 mol CO₂

O₂ is the limiting reactant because it gives the smaller amount of CO₂.

==============

Step 3. Calculate the <em>moles of C₃H₈ consumed</em>.

The molar ratio of C₃H₈:O₂ is 1:5.

Moles of C₃H₈ = 4.00 × ⅕

Moles of C₃H₈ = 0.800 mol C₃H₈

7 0
3 years ago
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