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3 years ago

Flashlight has resistance of 2.4 what voltage is applied by the batteries if the current is 2.5a

Physics

1 answer:

Sergeeva-Olga [200]3 years ago

5 0

Answer:

6 voltage is applied by the batteries.

Explanation:

To solve this sort of problem involving current, resistance and voltage, we use the relation: Voltage= Current x Resistance.

From the problem, the following have been given:

Resistance= 2.4 ohms.

Current= 2.5 amps.

Required: Voltage?

Fix the values of current and resistance into the relation:

Voltage= 2.5 x 2.4

=6 volts.

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What is the formula for the Total input energy? Pls help I have the test tomorrow Xxxx

arsen [322]

Answer:

The formula that links energy and power is: Energy = Power x Time. The unit of energy is the joule, the unit of power is the watt, and the unit of time is the second.

Explanation:

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3 years ago

In the ENGR 10 lab (E391), there are 50 long light bulbs (P=100 W) and 30 regular bulbs (P=60 W). How much energy is consumed li

Alenkinab [10]

Answer:

Total energy saving will be 0.8 KWH

Explanation:

We have given there are 50 long light bulbs of power 100 W so total power of 50 bulb = 100×50 = 5000 W = 5 KW

30 bulbs are of power 60 W

So total power of 30 bulbs = 30×60 = 1800 W = 1.8 KW

Total power of 80 bulbs = 1.8+5 = 6.8 KW

Total time = 3 hour

We know that energy $E=power\times time=6.8\times 3=20.4KWH$

Now power of each CFL bulb = 25 W

So power of 80 bulbs = 80×25 = 2000 W = 2 KW

Energy of 80 bulbs = 2×3 = 6 KWH

So total energy saving = 6.8-6 = 0.8 KWH

6 0

4 years ago

Part F A system experiences a change in internal energy of 14 kJkJ in a process that involves a transfer of 36 kJkJ of heat into

Molodets [167]

Answer:

Explanation:

According to first law of thermodynamics :

Q = ΔE + W

Q is heat added , ΔE is increase in the internal energy of the system and W is work done by the system .

Here Q = 36 KJ

ΔE = 14 kJ

Putting the values in the equation

36 = 14 + W

W = 36 - 14

= 22 kJ .

Work done by gas or system = 22 kJ.

3 0

3 years ago

3. If the net work done on an object is negative, then the object's kinetic energy

g100num [7]

Answer:

I think the answer is B I hope this helps also Im sorry If I'm wrong

4 0

3 years ago

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass 2kg. When a certain con

BARSIC [14]

Answer:

The acceleration of the second object is 4 m/s².

Explanation:

Given that,

when the a constant force acts upon an object, the acceleration varies inversely with its mass .

$mass\propto \frac{1}{acceleration}$

We can rewrite the equation as

$\frac{m_1}{m_2}=\frac{a_2}{a_1}$

When an a certain constant force acts upon an object with mass 2 kg , the acceleration of the object is 26 m/s².

Here, $m_1$ = 2 kg, $a_1$ = 26 m/s², $m_2$ = 13 kg and $a_2=?$

$\frac{m_1}{m_2}=\frac{a_2}{a_1}$

$\frac{2}{13}=\frac{a_2}{26}$

$\Rightarrow \frac{a_2}{26}= \frac{2}{13}$

$\Rightarrow {a_2}= \frac{2}{13}\times 26$

$\Rightarrow a_2=4$ m/s²

The acceleration of the second object is 4 m/s².

3 0

3 years ago